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Klio2033 [76]
3 years ago
8

A 50kg box is pulled on by a rope. The rope applies a horizontal force of 180 N to the box. What is the normal force exerted on

the box by the floor?
Physics
1 answer:
Over [174]3 years ago
4 0
The normal force would be the opposing and equal force to gravity ...  that is why the box isn't floating or going through the ground ... this is Newton's third law of motion

 
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Which kinds of objects emit visible light in the electromagnetic spectrum?
Triss [41]

Answer : Relatively hot objects

Explanation : We know that, the temperature of the objects is inversely proportional to their wavelengths. The objects emitting radiation in the visible region have short wavelength and hence are relatively hotter.

We know the range of wavelength of the visible spectrum is from 400 nm to 780 nm.





3 0
3 years ago
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HELP!!!! WILL MARK BRAINLIEST!!!! IF YOU LEAVE AN ANSWER EXPLAIN! THANKS
Travka [436]

Answer:

the answer is C

Explanation:

we know this because if you compare the graphs and look at the direction. it isn't always in the explanation or the few sentences they gave you at the top. also, look at the waves, you can see in Davids drawing that it is directly straight up, A and B do not represent that. A isn't even a valid answer. Notice also in A that the arrow is going in the completely different direction than in Davids drawing. B is also going a different direction even though it is only turned a little bit although if it was straight up like Davids drawing then it would most likely be a correct answer. C does have one arrow going a different direction but look at how it has two, showing in which if the waves were to turn then the arrow is still valid

7 0
3 years ago
A diverging lens (f1 = -12.0cm) is located 50.0 cm to the left of a converging lens (f2 = 34.0 cm). A 2.0 cm-tall object stands
pishuonlain [190]

Answer:

The final image relative to the converging lens is 34 cm.

Explanation:

Given that,

Focal length of diverging lens = -12.0 cm

Focal length of converging lens = 34.0 cm

Height of object = 2.0 cm

Distance of object = 12 cm

Because object at focal point

We need to calculate the image distance of diverging lens

Using formula of lens

\dfrac{1}{v}=\dfrac{1}{f}-\dfrac{1}{u}

\dfrac{1}{v}=\dfrac{1}{-12}-\dfrac{1}{-12}

v=\infty

The rays are parallel to the principle axis after passing from the diverging lens.

We need to calculate the image distance of converging lens

Now, object distance is ∞

Using formula of lens

\dfrac{1}{v}=\dfrac{1}{34}-\dfrac{1}{\infty}

v=34

The image distance is 34 cm right to the converging lens.

Hence, The final image relative to the converging lens is 34 cm.

5 0
3 years ago
Conversion of one form of energy into another form is ​
Artist 52 [7]

Answer: energy transformation

5 0
2 years ago
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Which option is a force?<br> O A. Mass<br> O B. Velocity<br> O C. Acceleration<br> O D. Weight
olga_2 [115]

Answer:

Weight is a force.

Explanation:

Force acting on an object is defined in terms of mass and its acceleration. Its mathematical force is given by

F = ma

Weight of an object is force that the Earth exerts on an object. It can be given by the formula as follows :

W = mg

g is acceleration due to gravity on the surface of earth

Hence, the correct option is (d).

6 0
3 years ago
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