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Furkat [3]
3 years ago
6

Where are the physics in football

Physics
1 answer:
sasho [114]3 years ago
5 0

Answer:

The branch of physics that is most relevant to football is mechanics, the study of motion and its causes.

Explanation:

When the ball leaves the punter's foot, it is moving with a given velocity (speed plus angle of direction) depending upon the force with which he kicks the ball. The ball moves in two directions, horizontally and vertically. Because the ball was launched at an angle, the velocity is divided into two pieces: a horizontal component and a vertical component.

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Each bat can produce different frequencies of ultrasound. Explain why this is useful if there are many bats hunting together.
Crazy boy [7]

Answer: Although low frequency sound travels further than high-frequency sound, calls at higher frequencies give the bats more detailed information--such as size, range, position, speed and direction of a prey's flight. Thus, these sounds are used more often.

Explanation:

6 0
3 years ago
When a firecracker explodes, what types of energy does it give off?
fomenos
The answer is c. 
Sound, light and heat energy.

Hope this helped :)
7 0
3 years ago
Im back and need help
const2013 [10]

Always here to help. Bring it!!!

7 0
2 years ago
Calculate the fraction of methyl isonitrile molecules that have an energy of 160.0 kJ or greater at 510 K .
soldi70 [24.7K]

Answer:

4.0932672025\times 10^{-17}

Explanation:

E_a = Activation energy = 160 kJ

T = Temperature = 510 K

R = Universal gas constant = 8.314 J/mol K

The fraction of energy is given by

f=e^{-\dfrac{E_a}{RT}}\\\Rightarrow f=e^{-\dfrac{160000}{8.314\times 510}}\\\Rightarrow f=4.0932672025\times 10^{-17}

The fraction of energy is 4.0932672025\times 10^{-17}

3 0
3 years ago
A runner taking part in the 200-m dash must run around the end of a track that has a circular arc with a radius of curvature of
Leto [7]

Answer: 2.27\ m/s^2

Explanation:

Given

Length of the race track L=200\ m

the radius of curvature of the track r=29.5\ m

time taken to run on track is t=24.4\ s

Speed of runner is

\Rightarrow v=\dfrac{L}{t}=\dfrac{200}{24.4}\\\\\Rightarrow v=8.196\ m/s

Centripetal acceleration is

\Rightarrow a_c=\dfrac{v^2}{r}=\dfrac{8.196^2}{29.5}\\\\\Rightarrow a_c=2.27\ m/s^2

5 0
3 years ago
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