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Leona [35]
3 years ago
11

The pressure inside a gas cylinder is 3,506 mmHg ,how many atmospheres of pressure is the gas exerting on the cylinder

Chemistry
2 answers:
myrzilka [38]3 years ago
7 0

Answer: 4.613 atm

Explanation:

Pressure of the gas is defined as the force exerted by the particles on the walls of the container. It is expressed in various terms like 'mmHg', 'atm', 'kiloPascals' etc..

All these units of pressure are inter convertible.

We are given:

Pressure of the gas = 3506 mmHg

Converting this unit of pressure into 'atm' by using conversion factor:

760mmHg=1atm

3506mmHg=\frac{1}{760}\times 3506=4.613atm

Thus there will be 4.613 atm in 3506 mmHg.

Lorico [155]3 years ago
4 0

Below are the choices:

a)0.2168 atm

b)4.613 atm

c)34.60 atm

d467.4 atm

B is correct answer.


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3Mg^3(PO^4)^2 ——— how many atoms are there
AfilCa [17]

36 atoms

Explanation:

Compound:

                  3 Mg³⁺  (PO₄)²⁻

  The compound is 3Mg₂(PO₄)₃

An atom is the smallest indivisible particle of a substance

Elements are atoms that are different from one another.

A compounds is combination of elements to give a distinct matter.

     3Mg₂(PO₄)₃

Elements here are Mg, P and O

Atoms:

        2 Mg

         2 P

         8 O

This gives 12 atoms in all

since we have 3mole of the compound, number of atoms  = 3 x 12 = 36atoms

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3 years ago
What type of solution would have a pOH of 7
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*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

Answer: None of these, because it is a neutral solution

Explanation:

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Read 2 more answers
Which scientist's experiments proved the existence of the nucleus? Niels Bohr's J.J. Thomson's Robert Millikan's Ernest Rutherfo
bezimeni [28]

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Explanation:

5 0
3 years ago
How is nitrogen converted in the nitrogen cycle
castortr0y [4]

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nitrogen fixing bacteria

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5 0
3 years ago
At a pressure of 9.25×10−14 atm and an ordinary temperature of 300.0 K , how many molecules are present in a volume of 1.10 cm3
statuscvo [17]

Answer:

2.49 × 10⁶ molecules

Explanation:

Given data

  • Pressure (P): 9.25 × 10⁻¹⁴ atm
  • Temperature (T): 300.0 K
  • Volume (V): 1.10cm^{3} .\frac{1mL}{1cm^{3}} .\frac{1L}{1000mL} =1.10\times 10^{-3} L

We can calculate the moles of gas using the ideal gas equation.

P × V = n × R × T

n = P × V / R × T

n = 9.25 × 10⁻¹⁴ atm × 1.10 × 10⁻³ L / (0.0821 atm.L/mol.K) × 300.0 K

n = 4.13 × 10⁻¹⁸ mol

1 mole contains 6.02 × 10²³ molecules (Avogadro's number). The number of molecules in 4.13 × 10⁻¹⁸ moles is:

4.13 × 10⁻¹⁸ mol × (6.02 × 10²³ molecule/1 mol) = 2.49 × 10⁶ molecule

7 0
3 years ago
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