Let our basis for the calculation be 1 mol of the substance.
(1 mol)(102 g/mol) = 102 g
Determine the amount of C, H, and O in mole.
C = (102 g)(0.588)(1 mol/12 g) = 4.998 mols C
H = (102 g)(0.098)(1 mol/1 g) = 9.996 mols H
O = (102 g)(0.314)(1 mol/16 g) = 2 mols O
The empirical formula of the substance is C5H10O2. The molar mass of the empirical formula is 102. This means that this is also its molecular formula.
Answer:
a)
b)
![[PCl_5]=0.0375M](https://tex.z-dn.net/?f=%5BPCl_5%5D%3D0.0375M)
Explanation:
Hello!
a) In this case, since we can see that the second reaction is equal to the half of the first reaction, we can relate the equilibrium constants as shown below:
Thus, by plugging in the the equilibrium constant of the first reaction we obtain:
b) In this case, for the described reaction we can write:
Thus, the corresponding equilibrium expression is:
![K=\frac{[PCl_3][Cl_2]}{[PCl_5]}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%5BPCl_3%5D%5BCl_2%5D%7D%7B%5BPCl_5%5D%7D)
In such a way, since we know the equilibrium constant and the concentrations of PCl3 and Cl2 at equilibrium, we can compute the concentration of PCl5 at equilibrium as follows:
![[PCl_5]=\frac{[PCl_3][Cl_2]}{K}\\](https://tex.z-dn.net/?f=%5BPCl_5%5D%3D%5Cfrac%7B%5BPCl_3%5D%5BCl_2%5D%7D%7BK%7D%5C%5C)
![[PCl_5]=\frac{\frac{0.20mol}{4L} *\frac{0.12mol}{4L} }{0.04}](https://tex.z-dn.net/?f=%5BPCl_5%5D%3D%5Cfrac%7B%5Cfrac%7B0.20mol%7D%7B4L%7D%20%2A%5Cfrac%7B0.12mol%7D%7B4L%7D%20%7D%7B0.04%7D)
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Answer:
running water and glaciers
Answer is: 0,327 g/l.
<span>Ideal gas law: pV = nRT.
</span><span>V - volume, the amount of space occupied by the gas.
</span><span>p - pressure ,1 atm = 760 torr = 760 mmHg.
</span><span>n - amount of substance.
</span>T - temperature, 273 K = 0°<span>C. T = 25 + 273 = 298K.
</span>R - ideal gas constant,<span> R = 0,08206 L</span>·atm/mol·K<span>.
</span>d(He) = M·p ÷ R·T.
d - density.
M - molar mass.
d(He) = 4g/mol · 2atm ÷ 298K · 0,08206 L·atm/mol·K = 0,327 g/l.
Answer:.603moles
Explanation:do given over 1 so 66.38 over 1 then multiply by 1 over 110.035344(the atomic mass of KMnO) and then you get the answear
