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3 years ago

Which kingdom does the owl belong to

1 answer:

8 0

Owls, birds of the order Strigiformes, include about 200 species of mostly solitary and nocturnal birds of prey typified by an upright stance, a large, broad head, binocular vision and binaural hearing, and feathers adapted for silent flight. Exceptions include the diurnal northern hawk-owl and the gregarious burrowing owl.Owls hunt mostly small mammals, insects, and other birds, although a few species specialize in hunting fish. They are found in all regions of the Earth except Antarctica and some remote islands.

Owls are divided into two families: the true owls, Strigidae; and the barn-owls, Tytonidae.

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IMPORTANT QUESTION ANSWER QUICK PLEASE!!!!!!

Flura [38]

Ⓘ ⒷⒺⓁⒾⒺⓋⒺ ⒾⓉ ⒾⓈ Ⓒ ⒽⒶⓋⒺ Ⓐ ⒼⓄⓄⒹ ⒹⒶⓎ

7 0

3 years ago

Some unpolarized light has an intensity of 1375 W/m2 before passing through three polarizing filters. The transmission axis of t

chubhunter [2.5K]

Answer:

intensity of the light that emerges from the three filters is 560.80 W/m²

Explanation:

Given data

intensity I = 1375 W/m2

angle 1 = 31.0°

angle 2 = 41.0°

to find out

intensity of the light that emerges from the three filters

solution

we know intensity of light pass 1st polarize = I/2 = 1375 / 2 = 687.5 W/m2

so intensity after 2nd polarize pass = I 1st cos²(θ)

I 2nd = 687.5 cos²(31) = 687.5 ( 0.836754) = 575.27 W/m2

and

intensity after 3rd polarize pass = I 2nd cos²(θ)

I 3rd = 575.27 cos²(41) = 575.27 (0.974839) = 560.80 W/m2

so that intensity of the light that emerges from the three filters is 560.80 W/m²

4 0

4 years ago

The first-order rearrangement of CH3NC is measured to have a rate constant of 3.61 × 10–15 s–1 at 298 K and a rate constant of 8

netineya [11]

Answer:

The activation energy for this reaction, Ea = 159.98 kJ/mol

Explanation:

Using the Arrhenius equation as:

$ln\frac {K_2}{K_1}=-\frac {E_a}{R}\times (\frac {1}{T_2}-\frac {1}{T_1})$

Where, Ea is the activation energy.

R is the gas constant having value 8.314 J/K.mol

K₂ and K₁ are the rate constants

T₂ and T₁ are the temperature values in kelvin.

Given:

K₂ = 8.66×10⁻⁷ s⁻¹ , T₂ = 425 K

K₁ = 3.61×10⁻¹⁵ s⁻¹ , T₁ = 298 K

Applying in the equation as:

$ln\frac {8.66\times 10^{-7}}{3.61\times 10^{-15}}=-\frac {E_a}{8.314}\times (\frac {1}{425}-\frac {1}{298})$

Solving for Ea as:

Ea = 159982.23 J /mol

1 J/mol = 10⁻³ kJ/mol

Ea = 159.98 kJ/mol

7 0

3 years ago

Una mujer de 65 kg, se balancea sobre uno de los tacones de sus zapatos. Si el tacón es circular con un radio de 0,5 cm, ¿qué pr

goldenfox [79]

Explicacion

m = 65 kg

g = 10 m/s²

r = 0.5 cm (1m / 100 cm) = 0.05 m

A = π r² = π (0.05 m)² = 0.00785 m²

F =W = m g = 65 kg(10 m/s²) = 650 N

P = F/A = 650 N / 0.00785 m² = 82802.54 N/m²

7 0

3 years ago

Tidal friction is slowing the rotation of the Earth. As a result, the orbit of the Moon is increasing in radius at a rate of app

melomori [17]

Answer:

967500000 years

Explanation:

The Speed at which the radius of the orbit of the Moon is increasing is 4 cm/yr

Converting to m

1 m = 100 cm

$1\ cm=\frac{1}{100}\ m$