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Georgia [21]
3 years ago
11

Which kingdom does the owl belong to

Physics
1 answer:
Hoochie [10]3 years ago
8 0

<em>Owls, </em><em>birds</em><em> of the </em><em>order</em><em> Strigiformes, include about 200 </em><em>species</em><em> of mostly </em><em>solitary</em><em> and </em><em>nocturnal</em><em> </em><em>birds of prey</em><em> typified by an upright stance, a large, broad head, binocular vision and binaural hearing, and feathers adapted for silent flight. Exceptions include the diurnal </em><em>northern hawk-owl</em><em> and the gregarious </em><em>burrowing owl</em><em>.</em><em>Owls hunt mostly small </em><em>mammals</em><em>, </em><em>insects</em><em>, and other birds, although a few species specialize in hunting </em><em>fish</em><em>. They are found in all regions of the Earth except </em><em>Antarctica</em><em> and some remote islands.</em>

<em>Owls are divided into two </em><em>families</em><em>: the </em><em>true owls</em><em>, Strigidae; and the </em><em>barn-owls</em><em>, Tytonidae.</em>

i think you can find an answer from this ;)

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A hungry 169169 kg lion running northward at 77.377.3 km/hr attacks and holds onto a 31.731.7 kg Thomson's gazelle running eastw
navik [9.2K]

Answer:  75,242.9 m/s

Explanation:

from the question we are given the following parameters

mass of Lion (ML) = 169,169 kg

velocity of lion (VL) = 777,377.7 m/s

mass of Gazelle (Mg) = 31,731.7 kg

velocity of Gazelle (Vg) = 63,863.8 kg

mass of Lion and Gazelle (M) = 200,900.7 kg

velocity of Lion and Gazelle (V) = ?

The first figure below shows the motion of the Lion and Gazelle with their direction.

The second diagram shows the motion of the Lion and Gazelle with their directions rearranged to form a right angle triangle.

from the triangle formed we can get the velocity of the Lion and Gazelle immediately after collision using their momentum and Phytaghoras theorem

momentum = mass x velocity

momentum of the Lion = 169,169 x 77,377.3 = 13,089,840,463.7 kgm/s

momentum of the Gazelle = 31,731.7 x 63,863.8 = 2,026,506,942.46 kgm/s

momentum of the Lion and Gazelle = 200,900.7  x V

now applying Phytaghoras theorem we have

13,089,840,463.7 + 2,026,506,942.46 =  200,900.7 x V

15,116,347,406.16 = 200,900.7 x V

V = 75,242.9 m/s

7 0
2 years ago
Read 2 more answers
The sound level at a distance of 2.30 m from a source is 115 dB. At what distance will the sound level have the following values
Aleksandr [31]

Answer:

distance is 13 m for 100 dB

distance is 409 km for 10 dB

Explanation:

Given data

distance r = 2.30 m

source β = 115 dB

to find out

distance at sound level 100 dB and 10 dB

solution

first we calculate here power and intensity and with this power and intensity we will find distance

we know sound level  β  = 10 log(I/I_{0})        ......................a

put here value (I/I_{0}) = 10^−12 W/m² and  β = 115

115  = 10 log(I/10^−12)

so

I = 0.316228 W/m²

and we know power = intensity × 4π r²    ...............b

power = 0.316228 × 4π (2.30)²

power = 21.021604 W

we know at 100 dB intensity is 0.01 W/m²

so by equation b

power = intensity × 4π r²

21.021604 = 0.01 × 4π r²

so by solving r

r = 12.933855 m    = 13 m

distance is 13 m

and

at 10 dB intensity is 1 × 10^–11 W/m²

so by equation b

power = intensity × 4π r²

21.021604 = 1 × 10^–11 × 4π r²

by solving r we get

r = 409004.412465 m = 409 km

5 0
3 years ago
A box with a mass of 12.5kg sits on the floor how high would you need to lift it has a GPE of 568j
Degger [83]
GPE=mgh
m= 12.5kg
g= 9.81 always
h=?

568=12.5*9.81*h
Solve for h
You will get 4.63m
4 0
3 years ago
1. What is the total distance traveled?<br> A 3.0m <br> B 4.0m <br> C 5.0m <br> D 6.0m
Ostrovityanka [42]

Answer:

c

Explanation:

7 0
2 years ago
Which statement about the reaction is correct?
balu736 [363]

Answer:

I think D am not pretty show

8 0
2 years ago
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