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katrin [286]
3 years ago
8

A force of 15 newtons is used to push a box along the floor a distance of 3 meters. How much work was done?

Physics
1 answer:
jeka57 [31]3 years ago
7 0

Answer:

<h3>The answer is 45 J</h3>

Explanation:

The work done by an object can be found by using the formula

<h3>workdone = force × distance</h3>

From the question

distance = 3 meters

force = 15 newtons

We have

workdone = 15 × 3

We have the final answer as

<h3>45 J</h3>

Hope this helps you

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A stone of mass 250 g is located at a height of 20 m calculate the potential energy of the stone?
irina1246 [14]

Answer:

50J

Explanation:

Potential energy = mass (kg) * gravitational accelerations (10N on earth) * height

250 g in kg = 0.25

0.25 * 10 * 20 = 50 J

6 0
3 years ago
A circuit with a resistance of 25 ohms is carrying a current of 2
-BARSIC- [3]
The heat developed can be calculated using the power rules as follows:

P = I x V = I^2 x R

First solution is to use the given values of I and R as follows:
P = I^2 x R = (2)^2 x 25 = 4 x 25 = 100 watt

Second solution is to use ohm's law to get V, then substitute to get the power as follows:
V = I x R = 2 x 25 = 50 volts
Power = V x I = 50 x 2 = 100 watt
7 0
3 years ago
How do i solve this step by step
NikAS [45]

Answer:

176.4 meters

Explanation:

The first equation is for average velocity.  The other three are the constant acceleration equations you'll need to know.

v = at + v₀

v² = v₀² + 2a(x − x₀)

x = x₀ + v₀ t + ½ at²

x is the final position

x₀ is the initial position

v is the final velocity

v₀ is the initial velocity

t is time

a is acceleration

Notice that the first equation is independent of position.

The second equation is independent of time.

The third equation is independent of final velocity.

So knowing which information you <em>don't</em> have will point you to which equation you should use.

Let's begin:

"Which one would be best to find the distance the object fell from free-fall if it fell for six seconds, assuming if fell in the absence of air resistance and it still hasn't hit the ground?  Solve this problem and show all steps of work."

We want to find the distance (change in position).  We're given the time (t = 6 s) and we're given the acceleration (free fall without air resistance, so a = -9.8 m/s²).

We aren't given the final velocity, so the equation we should use is the third one:

y = y₀ + v₀ t + ½ at²

Unfortunately, we aren't told the initial velocity, but if we assume that the object starts at rest, then v₀ = 0 m/s.  Substituting all values:

y = y₀ + (0 m/s) (6 s) + ½ (-9.8 m/s²) (6 s)²

y − y₀ = -176.4 m

The displacement is -176.4 m.  Distance is the magnitude of displacement, so we can say the object fell 176.4 meters.

3 0
3 years ago
Which statement is true about using shorter,steeper inclined planes to lift an object?
Grace [21]

Is there supposed to be options with this or are those the options there, steeper and smaller

7 0
3 years ago
How do you solve this system of equations. x+y−z = 0 5.08x − 9.96y = 5.31 9.96y − 14.72z = −10.37?
liraira [26]
Just know this:
x + y < or equal to z
5 0
4 years ago
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