Answer:
Li (s) + H₂O (l) → 1/2 H₂ (g) + LiOH (aq)
Explanation:
Lithium metal reacts with liquid water to form hydrogen gas and aqueous lithium hydroxide
2Li (s) + 2H₂O (l) → H₂ (g) + 2LiOH (aq)
We can divide stoichiometry coefficients /2, to have the lowest stoichiometry.
Thus problem is providing us with the mass of iron (III) oxide as 12.4 g so the moles are required and found to be 0.0776 mol after the calculations:
<h3>Mole-mass relationships:</h3>
In chemistry, we use mole-mass relationships in order to calculate grams from moles and vice versa. In this case, since we are given the mass of iron (III) oxide as 12.4 g one can calculate the moles by firstly quantifying its molar mass:

Then, we prepare a conversion factor in order to cancel out the grams and thus, get moles:

Learn more about mole-mass relationships: brainly.com/question/18311376
Half-reaction for the cell's anode is given below:
Anode : 
The anode is defined as the electrode at which electrons leave the cell and oxidation occurs, and the cathode as the electrode at which electrons enter the cell and reduction occurs. The anode is usually the positive side.
Learn more about anode here:
brainly.com/question/4052514
Your given question is quite incomplete here is complete question.
A voltaic cell is based on the reduction of _ Agt(aq) to Ag(s) and the oxidation of Sn(s) to Sn2+(aql) : Part 1 Include the phases of all species in the chemical equation: (aqh Anode: Sn(s) Sn?+ (aq)
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Answer:
PRESSURE is right answer .
Explanation:
True.
For example: Sodium oxide and Nitric acid; both compounds contain oxygen.