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Assoli18 [71]
3 years ago
8

3. (05.04 MC)

Chemistry
1 answer:
Alex73 [517]3 years ago
8 0

Answer:

1.10 g H2

Explanation:

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A hydrate of CuSO4 has a mass of 12.98 g before heating. After heating, the mass of the anhydrous compound is found to be 9.70
MatroZZZ [7]
After the water is boiled off, the mass is 9.7 grams, so find the weight of the water.

12.98 - 9.7 = 3.28g H2O

Find how many moles of CuSO4 and H2O you have.

If there are about 18g per mole of H2O

3.28/18 = .1822 moles of H2O

If there are about 160g per mole of CuSO4

9.7/160 = .0606 moles of CuSO4

.1822/.0606 = 3

Ratio of H2O to CuSO4 = 1:3

Formula
<span>CuSO4.3H2O
</span>
Full Name
<span>Copper (II) Sulphate Trihydrate</span>


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