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ser-zykov [4K]
3 years ago
5

Which of Newton's Three Laws is BEST described by the following statement: A ball dropped from the 10th story of a hotel had mor

e force than when the same ball was dropped from the 5th story of the same hotel
Chemistry
1 answer:
Zolol [24]3 years ago
8 0

Answer:

I believe the answer is Newton's Second Law

Explanation:

Newton's Second Law states that the acceleration of an object will count on how much mass and the amount of force that is applied.

The bowling ball was dropped from the 10th story window and had more force than when the ball was dropped from the 5th story window because the 10th story window gave the bowling ball more acceleration.

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1. How would the series of figures change in the presence of a catalyst?
statuscvo [17]

No, it won't change the amount of reactants nor the products as a catalyst will only provide an alternative path where lower activation energy is needed for the process to take place.

hope this explains it

If it does, please give it a brainliest :)))

8 0
3 years ago
Read 2 more answers
The speed of a spaceship is going warp 7.58. What is the velocity of the spaceship in cm/min. Assume 1.00 warp = 2.5 times the s
grandymaker [24]

Answer : The velocity of the spaceship is, 3408.6\times 10^{10}cm/min

Solution :

As we are given that,

1.00\text{ wrap }=2.5\times \text{The speed of light}

The speed of a spaceship = 7.58 wraps

So, 7.58\text{ wrap }=7.58\times 2.5\times \text{The speed of light}

The speed of light = 2.9979\times 10^8m/s

Now put the value of speed of light in above expression, we get

So, 7.58\text{ wrap }=(7.58)\times (2.5)\times (2.9979\times 10^8m/s)=56.81\times 10^8m/s

The velocity of the spaceship = 56.81\times 10^8m/s

Now we have to convert the velocity of the spaceship m/s to cm/min.

Conversion :

(1 m = 100 cm)

(1 min = 60 sec)

The velocity of the spaceship = (56.81\times 10^8)\times 100\times 60cm/min=3408.6\times 10^{10}cm/min

Therefore, the velocity of the spaceship is, 3408.6\times 10^{10}cm/min

3 0
3 years ago
Why do compounds with strong intermolecular attractive forces have a higher boiling points than compounds with the weak intermol
Brut [27]

The boiling point is the temperature at which the vapour pressure of the solution or solvent becuase equal to the ambient pressure, and bubbles of vapour from directly in the liquid. The normal boiling point is specified when the ambient pressure ( And also thvapour pressure of the boiling liquid) is One atmosphere. Ans so where strong intermolecular forces of attraction operate for instance in Hydrogen-Bonded liquids, boiling point should be elevated. More energy has to be put into the system to disrupt the intermolecular force. And the best indicator or intermolecular or inter-particle force is boiling point.

3 0
3 years ago
Read 2 more answers
Practice 14.2: Predict the equilibrium constant for the first reaction given the equilibrium constants for the second and third
Finger [1]
Reverse the 2nd reaction,
CO2 + H2 -------> CO + H2O---- i

Now new equilibrium constant will be,
K' = 1/K2 = 10^-5

Adding i and last equation you'll get,
<span>CO2 (g) + 3 H2 (g)----->CH3OH (g) + H2O (g)
K1 = K' x K3 = 1.4 x 10^2 </span>
5 0
3 years ago
Read 2 more answers
A sample of gas occupies 806 mL at 26 degrees c and 1 atm. Find the volume of the gas at STP
Varvara68 [4.7K]
The standard temperature and pressure is 273 K and 1 atm. Since, pressure is not changed we can use Charle's law for the calculations.

<span>Charle's law says "at a constant pressure, the volume of a fixed amount of gas is directly proportional to its absolute temperature".

V α T 

Where V is the volume and T is the temperature in Kelvin of the gas. We can use this for two situations as,
V</span>₁/T₁ = V₂/T₂<span>

</span>V₁ = 806 mL<span>
T</span>₁ = 26 ⁰C = 299 K
V₂ <span>= ? </span><span>
T</span>₂ = 273 K<span>
<span>
By applying the formula,
</span></span>(806 mL / 299 K) = (V₂ / 273 K)

                       V₂ = 735. 91 mL

<span>
Hence, the answer is "a".</span>

6 0
3 years ago
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