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SashulF [63]
2 years ago
6

What is glucose? How is it formed?​

Chemistry
2 answers:
Alik [6]2 years ago
6 0
Glucose is a simple sugar with the molecular formula C6H12O6. It is a carbohydrate.
Tcecarenko [31]2 years ago
4 0

Answer:

Glucose is a simple sugar with the molecular formula C₆H₁₂O₆. Glucose is the most abundant monosaccharide, a subcategory of carbohydrates.

Glucose is mainly made by plants and most algae during photosynthesis from water and carbon dioxide, using energy from sunlight, where it is used to make cellulose in cell walls, which is the most abundant carbohydrate.

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What is the formal charge on the hydrogen atom in hbr? use the periodic table as needed?
Westkost [7]
A covalent bond is formed between H and Br
The structure of HBr is as follows
H —Br
Formal charge for atoms are the charges for individual atoms in compounds.
Formal charge can be calculated as follows ;
Formal charge of atom = number of valence electrons -( number of bonds + number of lone pair electrons)
H has 1 valence electron, 1 bond and 0 number of lone pair electrons
Formal charge of H = 1 -1 -0 = 0
H has 0 charge
3 0
3 years ago
An artifact originally had 16 grams of​ carbon-14 present. the decay model upper a equals 16 e superscript negative 0.000121 ta=
xeze [42]

<u>Given:</u>

Initial amount of carbon, A₀ = 16 g

Decay model = 16exp(-0.000121t)

t = 90769076 years

<u>To determine:</u>

the amount of C-14 after 90769076 years

<u>Explanation:</u>

The radioactive decay model can be expressed as:

A = A₀exp(-kt)

where A = concentration of the radioactive species after time t

A₀ = initial concentration

k = decay constant

Based on the given data :

A = 16 * exp(-0.000121*90769076) = 16(0) = 0

Ans: Based on the decay model there will be no C-14 left after 90769076 years

3 0
3 years ago
Read 2 more answers
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Answer:

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7 0
3 years ago
Calculate the number of moles in a 14.5 gram sample of C4H10.
cricket20 [7]
Moles= mass divided by molar mass
Molar mass= 12.01(4) + 1.01(10)
                 = 58.14g/mol

Moles=14.5g / 58.14g/mol
         =0.249

Therefore there are approx 0.249 moles in a 14.5g sample of C4H10
6 0
2 years ago
How many significant numbers are there in 40.00
muminat

The answer to this is 4.

3 0
3 years ago
Read 2 more answers
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