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klasskru [66]
3 years ago
14

If I have 2.90 L of gas at a pressure of 5.00 atm and a temperature of 55.0 C what will be the temperature of the gas if I decre

ase the volume of the gas to 2.40 L and decrease the pressure to 3.00 atm?
Chemistry
1 answer:
Alex777 [14]3 years ago
4 0

Answer:

Vince Kutcher's I uh cc hgv gun cc GB cc by gabriel

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While 1 gram of fat provides 9 calories, 1 gram of glucose provides 4 calories. Why is that?
seropon [69]

Answer:

fat always has more calories than glucose does

Explanation:

hope hope this helps!

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3 years ago
This transition metal is in group 12 and has less than 34 protons
slava [35]

Zinc (Zn) has less than 34 protons, 30 to be exact, and is a transition metal in Group 12. Note: it is also called a "post-transition metal."

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3 years ago
Why do covalent compounds tend to have lower melting points than ionic compounds?
vitfil [10]
Because ionic compounds' strong bonds form network structures, which have a stronger attraction than the covalent compounds which are molecules.
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Read 2 more answers
Determine the value of the equilibrium constant, Kgoal, for the reaction C(s)+12O2(g)+H2(g)⇌12CH3OH(g)+12CO(g), Kgoal=? by makin
Licemer1 [7]

Answer:

1.71x10²⁷

Explanation:

If we sum 1/2 of (3) + 1/2 of (1):

1/2 (3.) C(s) + 1/2O₂(g) ⇌ CO(g), K₃ = √2.10×10⁴⁷  = 4.58x10²³

1/2 (1)   1/2CO₂(g) + 3/2H₂(g) ⇌ 1/2CH₃OH(g) + 1/2H₂O(g), K₁ = √1.40×10² = 11.8

C(s) + 1/2O₂(g) +<u> 1/2CO₂(g) </u>+<u> 3/2H₂(g</u>) ⇌ 1/2CH₃OH(g) + <u>1/2H₂O(g)</u> + <u>CO(g)</u>

K' = 4.58x10²³ * 11.8 = 5.42x10²⁴

+1/2 (2):

<u>1/2 CO(g)</u> +<u> 1/2H₂O(g)</u> ⇌<u> 1/2CO₂(g)</u> + <u>1/2H₂</u> (g), K = √1.00×10⁵ = 316.2

C(s) + 1/2O₂(g) + H₂(g) ⇌ 1/2 CHO₃H(g) + 1/2CO(g)

K'' = 5.42x10²⁴* 316.2 =

<h3>1.71x10²⁷</h3>

5 0
3 years ago
A large, semi-truck hauling a full load and a small car are traveling in the same direction. As they approach a sharp curve in t
WARRIOR [948]
The semi will have the hardest time changing direction because of its mass. The more mass there is, the more effort it takes to accelerate and decelerate as well as change direction.
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