A solution contains 45 grams of nitrogen gas and 40 grams of argon. What is the mole fraction of argon in this solution?

1 answer:

8 0

<span>0.38

You first calculate the total moles by dividing the grams by molecular weight:
45 g N2 / 28.02 g/mol = 1.6 mol N2
40 g Ar / 39.95 g/mol = 1.0 mol

Then you divide the moles of Ar by the total number of moles:
1.0 / (1.6 + 1.0) = 0.38 mol fraction</span>

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