The rate of reaction that can be measured in the dark by determining the amount of oxygen gas consumed in a period of time is the rate of respiration.
Why?
Plants can undergo two types of reactions involving oxygen:
- <u>Photosynthesis: </u>In this type of reaction, plants use energy from light to synthesize glucose. The chemical reaction for photosynthesis is: 6H₂O + 6CO₂ → C₆H₁₂O₆ + 6O₂, and this reaction produces oxygen gas in the presence of light, that means that to measure the rate of photsynthesis, you'll need to measure the amount of oxgen gas <u>produced</u> in a period of time.
- <u>Respiration:</u> In this type of reaction, plants convert the energy stored in the chemical bonds of molecules such as glucose to obtain energy. The chemical reaction for respiration is: C₆H₁₂O + 6O₂ → 6H₂O + 6CO₂, since this reaction consumes oxygen gas in the dark, that means that to measure the rate of respiration, you'll need to measure the amount of oxygen gas <u>consumed</u> in a period of time.
Have a nice day!
same family or group called Alkali metals
Answer:
As more sodium chloride is dissolved, higher is the boiling point of the solution
Explanation:
The boiling point- the temperature at which the solution boils- will increase as more solute is added. That is a colligative property called <em>boiling point elevation</em>. Colligative propeties are those that depend on the number of particles of solute in a solution. As more solute is added (sodium chloride or NaCl), more particles of solute will be present in the solution and the boiling point of the solution will be higher. The mathematical expression for the boiling point elevation (ΔTb) is the following:
ΔTb= Kb x m
Where Kb is a molal constant and m is the molality of the solution. That expression shows that the elevation of boiling point depends on the concentration of the solute expressed in terms of moles per mass of solution.
The answer is B. Flammability
m(O2)=50g
m(H2)=50g
m(H2O)-?
n2(H2)-?
2H2 + O2 = 2H2O
n(O2)= m (O2)/M(O2) =50g / 32 g/mol= 1,56 mol.
n(H2)= m (H2)/M(H2) =50g / 2 g/mol= 25 mol.
Since oxygen gas is the limiting reactant,
n(O2)< 2 n(H2) from reaction.
n(H2O)= 2n(O2)= 2n (H2 reac.)=2*1,56 mol=3,12mol.
m(H2O)=n(H2O)*M(H2O)= 3,12mol* 18 g/mol.
n2(H2)= n(H2) - n (H2 reac.)=25mol - 3,12mol=21,88mol.