Answer:
A) The continents and ocean basins undergo continuous change. Both are parts of lithospheric plates that move against each other. B) Divergent plate in Mid-Atlantic Ridge with material flowing into the ocean. C) A plate moved over a stationary site of magma upwelling "Hot Spot" and created a volcanic island chain over the time
Explanation:
A) The basic thought is, that instead of being permanent fixtures of the earth's surface, the continents and ocean basins undergo continuous change. Both are parts of lithospheric plates that move against each other, and in the process new crust is created at midoceanic ridges (spreading centers), and old crust is consumed at convergent plate boundaries (subduction zones).
B) There are basically three different types of plate boundaries:
Divergent boundaries -- where new crust is generated as the plates pull away from each other.
Convergent boundaries -- where crust is destroyed as one plate dives under another.
Transform boundaries -- where crust is neither produced nor destroyed as the plates slide horizontally past each other.
The best known of the divergent boundaries is the Mid-Atlantic Ridge. This submerged mountain range, which extends from the Arctic Ocean to beyond the southern tip of Africa, is but one segment of the global mid-ocean ridge system that encircles the Earth.
C) The linear arrangement of many seamounts indicates that they formed because the plate moved over a stationary site of magma upwelling, a so called mantle "Hot Spot". Seamounts are submarine volcanoes that may finally build above the water level, in which case they are called islands. If seamounts rise above sea level (due to buildup of material in a cone or upwelling mantle pushes up plate), they are subject to wave erosion and colonization by reefs, with both processes tending to create a flat top on the original volcanic cone.
Answer: Option (B) is the correct answer.
Explanation:
In a solid, molecules are held together by strong intermolecular forces of attraction. As a result, they are unable to move from their initial place but they can vibrate at their mean position.
Hence, in solid substances the molecules have low kinetic energy.
Whereas in liquids, the molecules are held by less strong intermolecular forces of attraction as compared to solids. Due to which they are able to slide past each other. Hence, they have medium kinetic energy.
In gases, the molecules are held by weak Vander waal forces. Hence, they have high kinetic energy due to which they move rapidly from one place to another leading to more number of collisions.
Hence, gases are able to expand more rapidly as compared to liquids.
Thus, we can conclude that out of the given options solid = low; liquid = medium; gas = high, combination of the state of matter and the corresponding dryer speed is correct.
Answer: 24 m
explanation: it would be 24 because if it’s 12 m there and then 12 m back then that would be 24 m all together . if it’s 12 all together there and back,, the answer would be 6 m there and 6 m back:)
hope this helped in some type of way !
Answer:
clc
clear all
close all
format long
A=load('xyg1.mat');
x=A(:,1);
y=A(:,2);
[z,N,R2]=polyfitsystem(x,y,0.95)
function [z,N,R2]=polyfitsystem(x,y,R2)
for N=1:20
z=polyfit(x,y,N);
SSR=sum((y-polyval(z,x)).^2);
SST=sum((y-mean(y)).^2);
s=1-SSR/SST;
if(s>=R2)
R2=s;
break;
end
end
xx=linspace(min(x),max(x));
plot(x,y,'o',xx,polyval(z,x));
xlabel('x');
ylabel('y(x)');
title('Plot of y vs x');
end
Explanation:
Answer:
D) The worker will accelerate at 2.17 m/s² and the box will accelerate at 1.08 m/s²
, but in opposite directions.
Explanation:
Newton's third law
Newton's third law or principle of action and reaction states that when two interaction bodies appear equal forces and opposite directions. in each of them.
F₁₂= -F₂₁
F₁₂: Force of the box on the worker
F₂₁: Force of the worker on the box
Newton's second law
∑F = m*a
∑F : algebraic sum of the forces in Newton (N)
m : mass in kilograms (kg)
a : acceleration in meters over second square (m/s²)
Formula to calculate the mass (m)
m = W/g
Where:
W : Weight (N)
g : acceleration due to gravity (m/s²)
Data
W₁ =1.8 kN : box weight
W₂ = 0.900 kN : worker weight
F₂₁ = 0.200 kN
F₁₂ = - 0.200 kN
g = 9.8 m/s²
Newton's second law for the box
∑F = m*a
F₂₁ = m₁*a₁ m₁=W₁/g
0.2 kN = (1.8kN)/(9.8 m/s²
) *a₁
a₁= 1.08 m/s² : acceleration of the box
Newton's second law for the worker
∑F = m*a
F₁₂ = m₂*a₂ , m₂=W₂/g
- 0.2 kN =( (0.9 kN) /(9.8 m/s²
) )*a₂
a₂= -2.17 m/s² : acceleration of the worker
