<span>How many electrons would it take to equal the mass of a proton:
Here's one way of finding the value of it:
=> number of electrons is equivalent to 1 proton.
Let's have an example.
1.6726*10 -24g
_______________
1 proton
______________
9.109*10- ^28g
_______________
1 electron
Based on the given example above, the electrons is 1 839 per 1 proton.
It's about 1800 electrons/proton.</span>
Answer:
a) P=0.25x10^-7
b) R=B*N2*E
c) N=1.33x10^9 photons
Explanation:
a) the spontaneous emission rate is equal to:
1/tsp=1/3 ms
the stimulated emission rate is equal to:
pst=(N*C*o(v))/V
where
o(v)=((λ^2*A)/(8*π*u^2))g(v)
g(v)=2/(π*deltav)
o(v)=(λ^2)/(4*π*tp*deltav)
Replacing values:
o(v)=0.7^2/(4*π*3*50)=8.3x10^-19 cm^2
the probability is equal to:
P=(1000*3x10^10*8.3x10^-19)/(100)=0.25x10^-7
b) the rate of decay is equal to:
R=B*N2*E, where B is the Einstein´s coefficient and E is the energy system
c) the number of photons is equal to:
N=(1/tsp)*(V/C*o)
Replacing:
N=100/(3*3x10^10*8.3x10^-19)
N=1.33x10^9 photons
Answer:
B= 3.33 m T
Explanation:
Given that
Speed ,C= 6 x 10⁶ m/s
d= 1 cm = 0.01 m
V= 200 V
The electric field E given as
V= E .d
E=Electric field
d=Distance
V=Voltage
200 = 0.01 x E
E=20000 V/m
The relationship between magnetic and electric field given as
E= C x B
20000 = 6 x 10⁶ x B
B =3333.333 x 10⁻⁶ T
B= 3.33 x 10⁻³ T
B= 3.33 m T
Therefore the magnetic filed will be 3.33 m T.
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