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Brut [27]
3 years ago
7

In the diagram, what is happening to the temperature at Point B? Question 6 options: A. The temperature is rising as the molecul

es break apart from each other B. The temperature is not rising because the heat is being used to break the connections between the molecules C. The temperature is dropping as the molecules break apart from each other D. The temperature is rising as the substance melts E. The temperature is not rising because the molecules are slowing down

Physics
2 answers:
raketka [301]3 years ago
6 0
<span> B. The temperature is not rising because the heat is being used to break the connections between the molecules </span>
Lesechka [4]3 years ago
3 0

Answer: The correct answer is option D.

Explanation:

At point B, the temperature becomes constant which means that energy given to the substance is getting used in to the breaking of forces which are present in between the molecules of the substance. These forces are known as inter-molecular forces. Or we can also say that ,at point B the state of the substance is changing.

Hence, the correct answer is option D.

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A coil has 400 turns and self-inductance 7.50 mH. The current in the coil varies with time according to i = 1680 mA2 cos [πt/(0.
zhannawk [14.2K]

Answer:

(a) 1.58 V

(b) 0.0126 Wb

(c) 0.0493 V

Solution:

As per the question:

No. of turns in the coil, N = 400 turns

Self Inductance of the coil, L = 7.50 mH = 7.50\times 10^{- 3}\ H

Current in the coil, i = 1680cos[\frac{\pi t}{0.0250}] A

where

i_{max} = 1680\ mA = 1.680\ A

Now,

(a)  To calculate the maximum emf:

We know that maximum emf induced in the coil is given by:

e = \frac{Ldi}{dt}

e = L\frac{d}{dt}(1680)cos[\frac{\pi t}{0.0250}]

e = - 7.50\times 10^{- 3}\times \frac{\pi}{0.0250}\times \frac{d}{dt}(1680)sin[\frac{\pi t}{0.0250}]

For maximum emf, sin\theta should be maximum, i.e., 1

Now, the magnitude of the maximum emf is given by:

|e| = 7.50\times 10^{- 3}\times 1680\times 10^{- 3}\times \frac{\pi}{0.0250} = 1.58\ V

(b) To calculate the maximum average flux,we know that:

\phi_{m, avg} = L\times i_{max} = 7.50\times 10^{- 3}\times 1.680 = 0.0126\ Wb

(c) To calculate the magnitude of the induced emf at t = 0.0180 s:

e = e_{o}sin{\pi t}{0.0250}

e = 7.50\times 10^{- 3}\times sin{\pi \times 0.0180}{0.0250} = 2.96\times 10^{- 4} =0.0493\ V

7 0
3 years ago
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