NOTE question is incorrect: The question should be:
<span>How many moles of KCLO4 can be produced with 3.45 moles of KCl. Assume all other reactants are in excess.
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The reaction involving formation of KClO4 is
NaClO4 + KCl </span>→ KClO4 + NaCl
From above reaction, it can be seen that 1 mole of NaClO4 reacts with 1 mole of KCl to generate 1 mole of KClO4
Thus, if all other reactant are in excess, 3.45 moles of KCl will react with 3.45 moles of NaClO4 to form 3.45 moles of KClO4.
Answer for this question is 45,000
Answer:
Mass = 18 g
Explanation:
Given data:
Number of molecules of Dicarbon hexahydride = 3.58 × 10²³ molecules
Mass of Dicarbon hexahydride = ?
Solution:
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
For example,
3.58 × 10²³ molecules × 1 mol / 6.022 × 10²³ molecules
0.6 mol
Mass of Dicarbon hexahydride:
Mass = number of moles × molar mass
Mass = 0.6 mol × 30 g/mol
Mass = 18 g
Pt = p1 + p2 + p3, p1 = pp (CO) atm
2.68 atm = p1 + 1.56 atm + 0.65 atm
2.68 = p1 + 2.21
p1 = 2.68 - 2.21
p1 = 0.47 atm
