Horizontal is the correct one
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The answer is electrical energy
Amphiprotic compounds are able to both donate and accept a proton.
Amphiprotic compounds contain a hydrogen atom and lone pair of valence electron.
For example, HSO₃⁻ (hydrogen sulfate ion) is an amphiprotic compound.
Balanced chemical equation for reaction when HSO₃⁻ donate protons to water:
HSO₃⁻(aq) + H₂O(l) ⇄ SO₄²⁻(aq) + H₃O⁺(aq).
Ka = [SO₄²⁻] · [H₃O⁺] / [HSO₃⁻]
Balanced chemical equation for reaction when HSO₃⁻ accepts protons from water:
HSO₃⁻(aq) + H₂O(l) ⇄ H₂SO₄(aq) + OH⁻(aq).
Kb = [H₂SO₄] · [OH⁻] / [HSO₃⁻]
Water (H₂O), amino acids, hydrogen carbonate ions (HCO₃⁻) are examples of amphiprotic species.
Another example, water is an amphiprotic substance:
H₂O + HCl → H₃O⁺ + Cl⁻
H₂O + NH₃ → NH₄⁺ + OH⁻
More about amphiprotic compounds: brainly.com/question/3421406
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Answer:
a chemical equation is a method of representing chemical reaction by using symbols and formulas
Answer:
Explanation:
d =
m
V
m = d×V
V =
m
d
DENSITY
Density is defined as mass per unit volume.
d =
m
V
Example:
A brick of salt measuring 10.0 cm x 10.0 cm x 2.00 cm has a mass of 433 g. What is its density?
Step 1: Calculate the volume
V = lwh = 10.0 cm × 10.0 cm × 2.00 cm = 200 cm³
Step 2: Calculate the density
d =
m
V
=
433
g
200
c
m
³
= 2.16 g/cm³
MASS
d =
m
V
We can rearrange this to get the expression for the mass.
m = d×V
Example:
If 500 mL of a liquid has a density of 1.11 g/mL, what is its mass?
m = d×V = 500 mL ×
1.11
g
1
m
L
= 555 g
VOLUME
d =
m
V
We can rearrange this to get the expression for the volume.
V =
m
d
Example:
What is the volume of a bar of gold that has a mass of 14.83 kg. The density of gold is 19.32 g/cm³.
Step 1: Convert kilograms to grams.
14.83 kg ×
1000
g
1
k
g
= 14 830 g
Step 2: Calculate the volume.
V =
m
d
= 14 830 g ×
1
c
m
³
19.32
g
= 767.6 cm³