In this picture there is a circuit and the boxes are circuit component please tell how many nodes are there in circuit?

What work is done by the electric force when the charge moves a distance of 2.70 m at an angle of 45.0∘ downward from the horizo

Andreyy89

Incomplete question as many data is missing.I have assumed value of charge and electric field.The complete question is here

A charge of 28 nC is placed in a uniform electric field that is directed vertically upward and that has a magnitude of 5.00×10⁴ V/m.

What work is done by the electric force when the charge moves a distance of 2.70 m at an angle of 45.0 degrees downward from the horizontal?

Answer:

$W_{work}=2.67*10^{-3}J$

Explanation:

Given data

Charge q=28 nC

Electric field E=5.00×10⁴ V/m.

Distance d=2.70 m

Angle α=45°

To find

Work done by electric force

Solution

$W_{work}=F_{force}*D_{distance}Cos\alpha \\where\\F_{force}=q_{charge}*E_{Electric-Field}\\So\\W_{work}=qE*D*Cos\alpha \\W_{work}=(28*10^{-9}C )(5.00*10^{4}V/m )(2.70m)Cos(45)\\W_{work}=2.67*10^{-3}J$

8 0

3 years ago

A 2.0 x 10^3-kilogram car travels at a constant speed of 12 meters per second around a circular curve of radius 30. meters. What

Vikentia [17]

The magnitude of the centripetal acceleration of the car as it goes round the curve is 4.8 m/s²

<h3>Circular motion</h3>

From the question, we are to determine the magnitude of the centripetal acceleration.

Centripetal acceleration can be calculated by using the formula

$a_{c} =\frac{v^{2} }{r}$

Where $a_{c}$ is the centripetal acceleration

$v$ is the velocity

and $r$ is the radius

From the given information

$v = 12 \ m/s$

and $r = 30 \ m$

Therefore,

$a_{c} =\frac{12^{2} }{30}$

$a_{c} =\frac{144 }{30}$

$a_{c} = 4.8\ m/s^{2}$

Hence, the magnitude of the centripetal acceleration of the car as it goes round the curve is 4.8 m/s²

Learn more on circular motion here: brainly.com/question/20905151

4 0

2 years ago

An object exerts a reaction force when it

r-ruslan [8.4K]

Answer:

all the forces occur in pairs that if one object exerts a force on another object, then the second object exerts an equal and opposite reaction force on the first.

5 0

3 years ago

A boy reaches out of a window and tosses a ball straight up with a speed of 10 m/s. The ball is 20 m above the ground as he rele

kirill115 [55]

Explanation:

It is given that,

Speed of the ball, v = 10 m/s

Initial position of ball above ground, h = 20 m

(a) Let H is the maximum height reached by the ball. It can be calculated using the conservation of energy as :

$\dfrac{1}{2}mv^2=mgh'$

$h'=\dfrac{v^2}{2g}$

$h'=\dfrac{(10)^2}{2\times 9.8}$

h' = 5.1 m

The maximum height above ground,

H = 5.1 + 20

H = 25.1 meters

So, the maximum height reached by the ball is 25.1 meters.

(b) The ball's speed as it passes the window on its way down is same as the initial speed i.e. 10 m/s.

Hence, this is the required solution.

6 0

3 years ago

Investigators are researching the appearance of a strange movement of objects in what the local community considers a haunted ho

wolverine [178]

Answer:

0.18216 T

Explanation:

N = Number of turns = 219

A = Area = $\pi r^2$

r = Radius = 1 cm

$\omega$ = Angular speed = $40\times 2\pi$

Maximum emf is given by

$\epsilon=NBA\omega\\\Rightarrow B=\dfrac{\epsilon}{NA\omega}\\\Rightarrow B=\dfrac{3.15}{219\times \pi 0.01^2\times 40\times 2\pi}\\\Rightarrow B=0.18216\ T$

The strength of the magnetic field is 0.18216 T

8 0

3 years ago