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lana66690 [7]
2 years ago
7

A physicist measures the magnetic field at the center of a loop of wire with N number of turns (not a solenoid) and current I fl

owing through it. They then triple the number of coils and half the radius of the coil while keeping the current the same. How does the magnetic field compare in the new situation, B2, compared to the first measurement, B1?
a. B2 = (3/2)B1
b. B2 = 6B1
c. B2 = (2/3)B1
d. B2 = (1/6)B1
d. None of the above
Physics
1 answer:
KIM [24]2 years ago
3 0

Answer: B

Explanation:

1) Apply Ampere's Law to the loop

\int{B*} \, ds = u_0I

B(2\pi r)=u_0NI\\

The loop has a circumference of 2pir.

The current enclosed is multiplied by N because there is N distinct loops.

B_1= \frac{u_0NI}{2\pi r}

B_2=\frac{u_0(3N)I}{2\pi(0.5r) }

B_2=6 B_1

Answer is B

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Complete Question

A person throws a pumpkin at a horizontal speed of   4.0 m/s off a cliff. The pumpkin travels 9.5m horizontally before it hits the ground. We can ignore air resistance.What is the pumpkin's vertical displacement during the throw? What is the pumpkin's vertical velocity when it hits the ground?

Answer:

The  pumpkin's vertical displacement  is  H = 27 .67 \ m

The  pumpkin's vertical velocity when it hits the ground is  v_v__{f}} = 23.298 \  m/s

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    The horizontal distance traveled is  d =  9.5 \ m

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Now the vertical displacement is mathematically represented as

        H  =  v_v t  +  \frac{1}{2} a_v t^2

now the vertical velocity before the throw is  zero

    So

          H =  0 +  \frac{1}{2} (9.8) * (2.375)^2

          H = 27 .67 \ m

Now the final vertical velocity  is mathematically represented as

          v_v__{f}} =  v_v + at

  substituting values

             v_v__{f}} =  0 + (9.8)* (2.375)

            v_v__{f}} = 23.298 \  m/s

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