Answer:

Explanation:
Position of charge 3q is x = 0
position of charge -2q is x = a
so here we know that
when two charges are of opposite nature then the electric field will be zero on the line joining the two charges at the position near to smaller magnitude charge
So here the electric field will be zero if the field due to 3q is counterbalanced by field due to -2q
so here we can say





so we will have

so the x coordinate of this position is given as

Thermal expansion<span> is the tendency of matter to change in shape, area, and volume in response to a change in temperature, through </span>heat<span> transfer. Temperature is a monotonic function of the average molecular kinetic energy of a substance. When a substance is heated, the kinetic energy of its molecules increases.so this can result in.......heat</span>