Im not sure if this is physics or mathematics. but if 300 msec then per minute this will equal to 300 X 60 sec =18000 m per minute
Answer: the mass of the second ball is 2.631 kg
Explanation:
Given that;
m1 = 0.877 kg
Initial velocity = V0
Initial momentum = m1 × V0
final velocity of m1 is u1, final velocity of m2 is u2 = v0/2
now final momentum = m1 × u1 + m2 × u2
using momentum conservation;
m1×V0 = m1×u1 + m2×v0/2
m1×(v0 - u1) = m2×V0/2 ----- let this be equation 1
Now, for elastic collision;
m1×v0²/2 = m1×u1²/2 + m2×(v0/2)²/2
m1×(v0² - u1²) = m2×(v0/2)² --------- let this be equation 2
now; equation 2 / equation 1
: V0 + u1 = v0/2
2V0 + 2u1 = V0
2u1 = V0 - 2V0
u1 = -V0/2
now we insert in equ 1
m1×3V0/2= m2×V0/2
m1 × 3 = m2
m2 = 0.877 × 3
m2 = 2.631 kg
Therefore, the mass of the second ball is 2.631 kg
Answer:
549.9 ohms, 65.65 watts, the power went up
Explanation: power P = V²/R
v= 190volts , P =62watts
from P =V²/R
62=190²/R
making R the subject
R×62= 190²
62R =36100
R=36100/62
R=586.25 ohms
Resistance of each lamp = 586.26/18 =32.3ohms
a) resistance of the light string now = 17×32.3 = 549.9 ohms
b) P=V²/R
where R=549.9ohms , P=?
P=190²/549.9
P=36100/549.9
P=65.65watts
Power dissipated has increased( went up )
True because when the independent answer changes, then the dependent variable, which relies on the independent variable, changes.
