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Katen [24]
2 years ago
8

What is the enthalpy of reaction for the decomposition of calcium carbonate?

Chemistry
1 answer:
posledela2 years ago
5 0
The decomposition of calcium carbonate, CaCO3(s) --> CaO(s) + CO2(g), has the following values for free energy and enthalpy at 25.0°C. G = 130.5 kJ/mol. H = 178.3 kJ/mol.
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Which of the molecules represented below contains carbon with sp2 hybridization?
Darya [45]

Answer:

Explanation:

sp² hybridization is found in those compounds having double bond .

Out of the given compounds only C₂H₂Cl₂ has double bond so this compound contains carbon with sp² hybridization .

Rest have sp³ hybridization because they are saturated compounds .

3 0
3 years ago
think about items you or your family bought over the last week. what kind of packaging was around those items? How did you dispo
Sunny_sXe [5.5K]

Answer:

its not that hard, i mean its a question that you kinda have to answer yourself. its basically asking you to write down the items that your family brought over the last week. just think of the things that your parents or family brought home. then you have to tell them what packaging was around the items, for example, plastic. and then etc.

Hope that helps you!

7 0
3 years ago
Send Message
Veronika [31]

Answer:co2

Explanation:

7 0
3 years ago
12.00 moles of naclo3 will produce how many grams of O2? (Moles to Grams)
Sergeu [11.5K]
2NaClO₃   →  2NaCl  +  3O₂

mole ratio of NaClO₃  to  O₂  is  2  :  3

∴  if moles of NaClO₃  =  12 mol

then moles of O₂  =  \frac{12 mol   *   3}{2}
      
                             =  18 mol


Mass of O₂  =  mol of O₂  ×  molar mass of O₂
 
                    =  18 mol  × 16 g/mol
 
                    =  288 g

So I wasn't sure which equation to use since you did not specify so I just used the decomposition reaction.  If you should have used another reaction then just follow the same steps and you'll get your answer.




4 0
3 years ago
Choose all the right answers.
gayaneshka [121]
I think the answer is

Reduce friction

:)
8 0
2 years ago
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