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Naily [24]
3 years ago
14

A solution is created by dissolving 11.5 grams of ammonium chloride in enough water to make 255 mL of solution. How many moles o

f ammonium chloride are present in the resulting solution
Chemistry
1 answer:
Nata [24]3 years ago
3 0

Answer:

<h2>The no. of moles present in one liter solution is 0.843</h2>

Explanation:

Mass of ammonium chloride  = 11.5 gm

Molar mass  of ammonium chloride  = 53.491 gm

No. of moles

N = \frac{mass}{molar \ mass}

N = \frac{11.5}{53.491}

N = 0.215 moles

Molarity=  \frac{N}{volume}

molarity = \frac{0.215}{0.255}

M = 0.843 M

Thus the no. of moles present in one liter solution is 0.843

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<h3>Further explanation</h3>

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