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dimaraw [331]
3 years ago
8

Need help Read each statement. Then, list each predator and each prey.

Chemistry
1 answer:
yanalaym [24]3 years ago
6 0
Prey- Antelope, Predator- Cheetah
Predator- Owl Prey- Mouse
Prey- birds, mice, and rats, predator- Gila monsters
Predator- Raccoons, prey- Crickets, small mammals, grapes, and nuts
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Molar mass in sulfuric acid
EleoNora [17]

Hey there!

Sulfuric acid: H₂SO₄

H: 2 x 1.008 = 2.016

S: 1 x 32.065 = 32.065

O: 4 x 16 = 64

--------------------------------

                 98.081 g/mol

The molar mass of sulfuric acid is 98.081 g/mol.

Hope this helps!

8 0
2 years ago
The compound adrenaline contains 56.79% c, 6.56% h, 28.37% o, and 8.28% n by mass. what is the empirical formula for adrenaline?
Phoenix [80]
To determine the empirical formula of the compound given, we need to determine the ratio of each element in the compound. To do that we assume to have 100 grams sample of the compound with the given composition. Then, we calculate for the number of moles of each element. We do as follows:<span>
         mass        moles
C       56.79        4.73
H       6.56          6.50
O       28.37        1.77
N      8.28           0.59

Dividing the number of moles of each element with the smallest value, we will have the empirical formula:

</span>         moles                 ratio
C       4.73     / 0.59       8
H       6.50     / 0.59      11
O       1.77     / 0.59       3
N        0.59    / 0.59       1<span>
</span><span>
The empirical formula would be C8H11O3N.</span>
8 0
2 years ago
Explain what air is, where on Earth it occurs, and how it moves to create wind.
pickupchik [31]

Answer:

Wind is caused by differences of pressure in the Earth's atmosphere. Air from a high pressure area will move towards an area of low pressure. High winds are caused when air moves between areas with large differences in air pressure.

Explanation:

4 0
3 years ago
How much does it take to make a science explosion?
melomori [17]

Answer:

Explanation:

D I think I am dumb

sorry

6 0
3 years ago
Read 2 more answers
rate of a certain reaction is given by the following rate law: rate Use this information to answer the questions below. What is
Sunny_sXe [5.5K]

Complete Question

The  rate of a certain reaction is given by the following rate law:

            rate =  k [H_2][I_2]

rate Use this information to answer the questions below.

What is the reaction order in H_2?

What is the reaction order in I_2?

What is overall reaction order?

At a certain concentration of H2 and I2, the initial rate of reaction is 2.0 x 104 M / s. What would the initial rate of the reaction be if the concentration of H2 were doubled? Round your answer to significant digits. The rate of the reaction is measured to be 52.0 M / s when [H2] = 1.8 M and [I2] = 0.82 M. Calculate the value of the rate constant. Round your answer to significant digits.

Answer:

The reaction order in H_2 is  n =  1

The reaction order in I_2 is  m = 1

The  overall reaction order z =  2

When the hydrogen is double the the initial rate is   rate_n  =  4.0*10^{-4} M/s

The rate constant is   k = 35.23 \  M^{-1} s^{-1}

Explanation:

From the question we are told that

   The rate law is  rate =  k [H_2][I_2]

   The rate of reaction is rate =  2.0 *10^{4} M /s

Let the reaction order for H_2 be  n and for I_2  be  m

From the given rate law the concentration of H_2 is raised to the power of 1 and this is same with I_2 so their reaction order is  n=m=1

   The overall reaction order is  

               z  = n +m

               z  =1 +1

               z  =2

At  rate =  2.0 *10^{4} M /s

        2.0*10^{4}  = k  [H_2] [I_2] ---(1)

= >    k  = \frac{2.0*10^{4}}{[H_2] [I_2]  }

given that the concentration of hydrogen is doubled we have that

            rate  = k [2H_2] [I_2] ----(2)

=>      k = \frac{rate_n  }{ [2H_2] [I_2]}

 So equating the two k

           \frac{2.0*10^{4}}{[H_2] [I_2]  } = \frac{rate_n  }{ [2H_2] [I_2]}

    =>    rate_n  =  4.0*10^{-4} M/s

So when

      rate_x =  52.0 M/s

        [H_2] = 1.8 M

         [I_2] =  0.82 \ M

We have

      52 .0 =  k(1.8)* (0.82)

     k = \frac{52 .0}{(1.8)* (0.82)}

      k = 35.23 M^{-2} s^{-1}

     

     

3 0
2 years ago
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