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3 years ago

Need help Read each statement. Then, list each predator and each prey.

1 answer:

6 0

Prey- Antelope, Predator- Cheetah
Predator- Owl Prey- Mouse
Prey- birds, mice, and rats, predator- Gila monsters
Predator- Raccoons, prey- Crickets, small mammals, grapes, and nuts

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A 7.74 L balloon is filled with water at 3.88 atm. If the balloon is squeezed into a 0.23 L beaker and does NOT burst, what is t

Vladimir [108]

Answer:

131 atm

Explanation:

To find the new pressure, you need to use Boyle's Law:

P₁V₁ = P₂V₂

In this equation, "P₁" and "V₁" represent the initial pressure and volume. "P₂" and "V₂" represent the final pressure and volume. You can find the new pressure (P₂) by plugging the given values into equation and simplifying.

P₁ = 3.88 atm P₂ = ? atm

V₁ = 7.74 L V₂ = 0.23 L

P₁V₁ = P₂V₂ <----- Boyle's Law

(3.88 atm)(7.74 L) = P₂(0.23 L) <----- Insert values

30.0312 = P₂(0.23 L) <----- Simplify left side

131 = P₂ <----- Divide both sides by 0.23

6 0

2 years ago

- What is the concentration of hydrogen ions if the pH is 12?

ELEN [110]

Answer:

1 x 10^-12 mol dm^-3

Explanation:

[H+] = 10 ^ -pH

Therefore, pH 12 = 1 x 10^-12 hydrogen ion concentration

4 0

3 years ago

Which diagram shows the correct direction of electron flow in an electrolytic cell?

Alborosie

Answer:

Explanation:

4 0

2 years ago

What is the boiling point of 0.464 m lactose in water? (Kb of water = 0.512 oC/m). Enter your answer to 3 decimal places.

kirill [66]

Answer:

Boiling point for the solution is 100.237°C

Explanation:

We must apply colligative property of boiling point elevation

T° boiling solution - T° boiling pure solvent = Kb . m

m = molalilty (a given data)

Kb = Ebulloscopic constant (a given data)

We know that water boils at 100°C so let's replace the information in the formula.

T° boiling solution - 100°C = 0.512 °C/m . 0.464 m

T° boiliing solution = 0.512 °C/m . 0.464 m + 100°C → 100.237 °C

3 0

3 years ago

a sample of an oxide of antimony (sb) contain 19.75 g of antimony combine with 6.5 g of oxygen . what is the simplest formula fo

frez [133]

Explanation:

The given data is as follows.

Mass of antimony = 19.75 g

Molar mass of Sb = 121.76 g/mol

Therefore, calculate number of moles of Sb as follows.

Moles of Sb = $\frac{mass}{\text{molar mass}}$

= $\frac{19.75 g}{121.76 g/mol}$

= 0.162 mol

Mass of oxygen given is 6.5 g and molar mass of oxygen is 16 g/mol. Hence, moles of oxygen will be calculated as follows.

Moles of oxygen = $\frac{mass}{\text{molar mass}}$

= $\frac{6.5 g}{16 g/mol}$

= 0.406 mol

Hence, ratio of moles of Sb and O will be as follows

Sb : O

$\frac{0.162}{0.162} : \frac{0.406}{0.162}$

1 : 2.5

We multiply both the ratio by 2 in order to get a whole number. Therefore, the ratio will be 2 : 5.

Thus, we can conclude that the empirical formula of the given oxide is $Sb_{2}O_{5}$ .

4 0

3 years ago