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frez [133]
4 years ago
14

What is the density of a 15 g box measuring 10 cm hy 5 cm by 2 cm?

Physics
1 answer:
Dvinal [7]4 years ago
8 0

Answer:

The density of the box is 0.15 g/cm³

Explanation:

Given;

mass of the box, m = 15 g

dimension of the box, = 10 cm by 5 cm by 2 cm

Volume of the box, v = 10 cm x 5 cm x 2 cm = 100 cm³

The density of the box is given by;

Density = mass / volume

Density = 15 g / 100 cm³

Density = 0.15 g/cm³

Therefore, the density of the box is 0.15 g/cm³

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A car stands from rest and attains a speed of 20 m/s in 10 s. What distance will it cover ?​
sashaice [31]

Answer:

100m

Explanation:

100m

s=ut+1/2at^2

s= unknown, u=0, a=2, t=10

s=0*10+1/2(2)(10)^2

s=1/2(2)(100)

s=1(100)

displacement = 100 meters

4 0
3 years ago
A wire carrying a 30.0-A current passes between the poles of a strong magnet that is perpendicular to its field and experiences
Zanzabum

Answer:

1.79 T

Explanation:

Applying,

F = BILsin∅................ Equation 1

Where F = Force, B = magnetic field, I = current flowing through the wire, L = length of the wire, ∅ = angle between the magntic field and the force

make B the subject of the equation

B = F/ILsin∅............. Equation 2

From the question,

Given: F = 2.15 N, I = 30 A, L = 4.00 cm = 0.04 m, ∅ = 90° (perpendicular to the field)

Substitute these values into equation 2

B = 2.15/(30×0.04×sin90°)

B = 2.15/1.2

B = 1.79 T

Hence the average field strength is 1.79 T

8 0
3 years ago
During the deceleration of an ascending elevator, the normal force on the feet of a passenger is _____ her weight. During the de
gizmo_the_mogwai [7]

Answer: Smaller than ; larger than

Explanation:

When the elevator is moving in the upward direction, then the force acting on it is negative in nature because of

N= mg +ma, (g is gravity and a is acceleration)

here ma is negative so the N= mg-ma

Hence, it feels smaller than its original weight.

When the elevator is moving downward , then the force acting will be positive in nature

N= mg+ma,

here ma will be positive so it feels larger the original weight of passenger.

7 0
3 years ago
Describe at least three measures that ensure safety and prevent injury during a workout.
KonstantinChe [14]
Water - helps with dehydration.
instruction - help you understand how you need to do the workout.
trainers - wether it's an online trainer or a gym trainer they always say how to be safe while working out.
5 0
3 years ago
Read 2 more answers
A train traveling at 27.5 m/s accelerates to 42.4 m/s over 75.0 s. What is the displacement of the train in this time period
Sergio [31]

Answer:

2621.25 meters

Explanation:

First, write down what we are given.

Initial velocity = 27.5 m/s

Final velocity = 42.4 m/s

Time = 75 seconds

We need to look at the kinematic equations and determine which one will be best.  In this case, we need an equation with distance.  I am going to use v_{f}^{2} = v_{i}^{2} +2ad, but you can also use the other equation, x = v_{o}t+\frac{1}{2}at^{2}

We need to find acceleration.  To find it, we need to use the formula for acceleration: a = \frac{v_{f}-v_{i}}{t}.  Plugging in values, a = \frac{42.4-27.5}{75} = .199\ m/s^{2}

Next, plug in what we know into the kinematics equation and solve for distance.  42.4^{2} = 27.5^{2} + 2(.199)(d)\\d = 2621.25\ meters

7 0
3 years ago
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