A ball is thrown vertically down from the edge of a cliff with a speed of 4 m/s,
1 answer:
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Answer:
1. Distance travelled = 12 km.
2. Displacement = 8.6 km
Explanation:
From the question given above, the following data were obtained:
Distance 1 (d₁) = 7 km
Distance 2 (d₂) = 5 km
Total distance =?
Displacement =?
1. Determination of the distance travelled.
Distance 1 (d₁) = 7 km
Distance 2 (d₂) = 5 km
Total distance (dₜ) =?
dₜ = d₁ + d₂
dₜ = 7 + 5
dₜ = 12 km
2. Determination of the displacement.
In the attached photo, R is the displacement.
We can obtain the value of R by using the pythagoras theory as illustrated below:
R² = 7² + 5²
R² = 49 + 25
R² = 74
Take the square root of both side
R = √74
R = 8.6 km
Answer:
91.48N/m
Explanation:
In a spring-mass system undergoing a simple harmonic motion, the inverse of the frequency f, of oscillation is proportional to the square root of the mass m, and inversely proportional to the square root of the spring constant, k. This can be expressed mathematically as follows;
=
-----------(i)
From the question;
f = 3.26 Hz
m = 0.218kg
Substitute these values into equation (i) as follows;
=
[<em>Square both sides</em>]
()² = (
)²(
)
() =
²(
) [<em>Take </em>
<em> to be 3.142</em>]
() =
²(
)
() =
(
)
() = (
) [<em>Switch sides</em>]
() = (
) [<em>Re-arrange</em>]
() = (
) [<em>Cross-multiply</em>]
k = 8.608 x 10.6276
k = 91.48N/m
Therefore, the spring constant of the spring is 91.48N/m