I think the answer would be 70
All of the observations except "powerful gravitational field" are consistent with the current theory of black holes.
The gavitational field of a black hole is thought to be no different than that of an ordinary star with the same mass.
What it looks to be that you found in A was the "initial"...b/c the question asks:
<span>"how much energy does the electron have 'initially' in the n=4 excited state?" </span>
<span>"final" would be where it 'finally' ends up at, ie. its last stop...as for this question...the 'ground state' as in its lowest energy level. </span>
The answer comes to: <span>−1.36×10^−19 J</span>
You use the same equation for the second part as for part a.
<span>just have to subract the 2 as in the only diff for part 2 is that you use 1squared rather than 4squared & subract "final -initial" & you should get -2.05*10^-18 as your answer. </span>
Explanation:
33. The 1.5kg owl is now soaring at 20m/s. What is the owl’s KE?
a. Step 1: Formula <u>½mv²</u>
b. Step 2: Data m = <u>1</u><u>.</u><u>5</u><u> </u><u>kg</u>, v = <u>2</u><u>0</u><u> </u><u>m</u><u>/</u><u>s</u>
c. Step 3: Solve
KE = (1/2)(<u>1</u><u>.</u><u>5</u>)(<u>2</u><u>0</u>)² = <u>3</u><u>0</u><u>0</u><u> </u><u>J</u>
distance = 10km
time = 1 1/2 = 3/2 hours
speed = distance/time = 10 / 3/2 = 20/3 = 6.67 Km/h
