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Len [333]
3 years ago
6

On the Moon the acceleration due to gravity is about one sixth that on Earth. If a golfer on the Moon imparted the same initial

velocity to the ball as she does on the Earth, how much farther would the ball go?
Physics
1 answer:
swat323 years ago
6 0

Explanation:

We know that that the range of the ball on the earth

R_{earth}=\frac{v_o^2sin2\theta}{g_{earth}}

therefore, range of the ball on moon

R_{moon}=\frac{v_o^2sin2\theta}{g_{moon}}

R_{moon}=\frac{v_o^2sin2\theta}{g_{earth}/12}

therefore,

R_{moon}=6R_{earth}

Therefore, the range of ball will be 6 times on the moon than that on earth

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3 0
3 years ago
What types of energy do you acquire when you eat a bowl of hot vegetable soup?
Aleksandr-060686 [28]

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8 0
3 years ago
How large an expansion gap should be left between steel railroad rails if they may reach a maximum temperature 40.0°C greater th
ella [17]

Answer:

19.68 × 10⁻³ m

Explanation:

Given;

Original Length, L₁ = 41.0 m

Temperature Change, ΔT = 40.0°C

Thermal Linear expansion of steel is given to be, ∝_{steel} = 12 × 10⁻⁶ /°C

   Generally, Linear expansivity is expressed as;

                               ∝ = ΔL / L₁ΔT

Where

∝ is the Linear expansivity

ΔL is the change in length, L₂ - L₁

L₂ is the final length

L₁ is the original length

ΔT is the change in temperature θ₂ - θ₁ (Final Temperature - Initial Temperature)              

From equation of linear expansivity

                         ΔL = ∝_{steel}L₁ΔT

                         ΔL = 12 × 10⁻⁶ /°C × 41.0 m × 40.0 °C

                         ΔL = 19.68 × 10⁻³ m

                         ΔL = 19.68 mm

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