Hi there!
On a level road:
∑F = Ff (Force due to friction)
The net force is the centripetal force, so:
mv²/r = Ff
Rewrite the force due to friction:
mv²/r = μmg
Cancel out the mass:
v²/r = μg 
Solve for v:
v = √rμg
v = √(25)(9.81)(0.8) = 14.01 m/s
 
        
             
        
        
        
Explanation:
hope it's help you ok have a good day
 
        
             
        
        
        
A basic mechanical device that is used for applying a force.
Examples are: inclined plane, lever, wedge, wheel and axle, pulley, and screw...Hope this helps, have a BLESSED and wonderful day!
 
        
                    
             
        
        
        
Oh gosh oh I see it in my life face and
        
             
        
        
        
Answer:
<h2><em>
6000 counts per second</em></h2>
Explanation:
If a sample emits 2000 counts per second when the detector is 1 meter from the sample, then;
2000 counts per second = 1 meter ... 1
In order to know the number of counts per second that would be observed when the detector is 3 meters from the sample, we will have;
x count per second = 3 meter ... 2
Solving the two expressions simultaneously for x we will have;
2000 counts per second = 1 meter
x counts per second = 3 meter
Cross multiply to get x
2000 * 3 = 1* x
6000 = x
<em></em>
<em>This shows that 6000 counts per second would be observed when the detector is 3 meters from the sample</em>