Question

What is the buffer component ratio, (bro-)/(hbro) of a bromate buffer that has a ph of 8.08. ka of hbro is 2.3 x 10-9?

Answer 1

pKa= -log(ka)

= -log(2.3*10^-9)

= 8.64

Now pH can be calculated using equation:

pH=pka+log(BrO-)/(HBrO)

8.08 =8.64+log(BrO-)/(HBrO)

log(BrO-)/(HBrO)=8.08-8.64

= -0.56

(BrO-)/(HBrO)= 10^-0.56

=0.275