- The water in the pot becomes hotter as a result of heat transfer.
- <em>Energy can be transferred from a region to another , but there will still the same overall amount of energy</em> ( energy conservation)
- When a pot containing water is placed on the stove and heat is applied with the burner, there is a flow of heat from the burner to the water.
- Heat will be transferred from the burner to the pot, then there will be transferred of heat from the pot to the water, the molecules there in the water will be energized as a result of the heat transfer until the boiling point is reached.
- Energy transfer can take place in three form, this could be conduction, radiation or convention.
- Convention which is a cyclical process is the one that occurs in fluids only so as a result of convection , the water at the bottom will be heated and the molecules start moving and it will rise till it get to the water at the top of the pot.
<em>Therefore, the water is heated as a result of heat transfer.</em>
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Answer: I'm sure it's possible but we too lazy
Explanation:
Answer:
It will be reported too low.
Explanation:
To measure the specific heat of the metal (s), the calorimeter may be used. In it, the metal will exchange heat with the water, and they will reach thermal equilibrium. Because it can be considered an isolated system (there're aren't dissipations) the total amount of heat (lost by metal + gained by water) must be 0.
Qmetal + Qwater = 0
Qmetal = -Qwater
The heat is the mass multiplied by the specific heat multiplied by the temperature change. If c is the specific heat of the water:
m_metal*s*ΔT_metal = - m_water *c*ΔT_water
s = -m_water *c*ΔT_water / m_metal*ΔT_metal
So, if m_water is now less than it was supposed to be, s will be reported too low, because they are directly proportional.
