<span> When an </span>acid and a base<span> are placed together, they </span>react<span> to neutralize the </span>acid<span> and </span>base<span> properties, producing a salt. The H(+) cation of the </span>acid<span>combines with the OH(-) anion of the </span>base<span> to form water.</span>
Answer:
1.02mole
Explanation:
The reaction equation is given as:
2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O
Given:
Mass of H₂SO₄ = 50g
Unknown:
Number of moles of NaOH = ?
Solution:
To solve this problem, we first find the number of moles of the acid given;
Number of moles =
Molar mass of H₂SO₄ = 2(1) + 32 + 4(16) = 98g/mol
Now;
Number of moles =
= 0.51mole
From the balanced reaction equation:
1 mole of H₂SO₄ will be neutralized by 2 mole of NaOH
0.51 mole of H₂SO₄ will be neutralized by 2 x 0.51 = 1.02mole of NaOH
6 because the number of valence electrons is always the ones-place of any two-digit group number. So an element in group 18 would have 8 valence electrons
Hope this helps!
Answer:
The total pressure is 1.616 atm
Explanation:
First of all we say:
In a closed system, sum of partial pressures is the value for the total pressure.
In our system, we have gas A and B
Total pressure without the third gas is = 0.373 atm + 0.650 atm = 1.023 atm
As we add a third gas, with no change in volume or T°, let's find out by the Ideal Gases Law, its pressure:
P . V = n . R . T
P = ( n . R . T) / V
P = (0.220 mol . 0.082 . (273 + 21°C)) / 8.95L = 0.593 atm
273 + 21°C → Absolute value of T°
Let's sum the partial pressures, then:
0.373 atm + 0.650 atm + 0.593 atm = 1.616 atm.
It's ok to say that the total pressure was increased, because we have more gas now.