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3 years ago

What changes in color when bromine reacts with an alkene

Chemistry

2 answers:

vlabodo [156]3 years ago

7 0

Answer:

For bromine, the dark red color disappears quickly as the atoms of bromine bond with the atoms of carbon in the double bond.

Explanation:

Tresset [83]3 years ago

7 0

Answer:

Question: What Changes In Color Occur When Bromine Or KM_nO_4 Reacts With An Alkeline? For Bromine, The Dark Red Quickly As The Atom Of Bromine Bond With The Atom P Of Carbon In The Double Bond.

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Consider this question: What is the molarity of HCL if 35.23 mL of a solution of HCL contains 0.3366 g of HCL?

Crazy boy [7]

Answer: The molarity of HCl solution is 0.262 M

Explanation:

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Given mass of HCl = 0.3366 g

Molar mass of HCl = 36.5 g/mol

Volume of the solution = 35.23 mL

Putting values in above equation, we get:

$\text{Molarity of HCl}=\frac{0.3366g\times 1000}{36.5g/mol\times 35.23mL}\\\\\text{Molarity of HCl}=0.262M$

Hence, the molarity of HCl solution is 0.262 M.

6 0

2 years ago

When adjusted for any changes in ΔHΔH and ΔSΔS with temperature, the standard free energy change ΔG∘TΔGT∘Delta G_{T}^{\circ} at

STALIN [3.7K]

The equilibrium constant is 0.0022.

Explanation:

The values given in the problem is

ΔG° = 1.22 ×10⁵ J/mol

T = 2400 K.

R = 8.314 J mol⁻¹ K⁻¹

The Gibbs free energy should be minimum for a spontaneous reaction and equilibrium state of any reaction is spontaneous reaction. So on simplification, the thermodynamic properties of the equilibrium constant can be obtained as related to Gibbs free energy change at constant temperature.

The relation between Gibbs free energy change with equilibrium constant is ΔG° = -RT ln K

So, here K is the equilibrium constant. Now, substitute all the given values in the corresponding parameters of the above equation.

We get,

$1.22 * 10^{5} = - 8.314* 2400 * ln K$

$\\ 1.22 * 10^{5} = -19953.6 * ln K$

$ln K = \frac{-1.22*10^{5} }{19953.6} =-6.114\\\\k =e^{-6.114}=0.0022$

So, the equilibrium constant is 0.0022.

4 0

3 years ago

Nitrogen effuses through a pinhole 1.7 times as fast as another gaseous element under the same conditions. Estimate the other el

marysya [2.9K]

Answer:

80.92, Krypton

Explanation:

What is effusion?

• It is a process where gas escapes through a pinhole (a very small hole) into a region of low pressure or vacuum

Graham's law of effusion of gas

• states that at a given constant temperature and pressure, the rate of effusion of gases is inversely proportional to the square root of their molar masses

$\boxed{ \frac{Rate_1}{Rate_2} = \sqrt{ \frac{M_2}{M_1} } }$

Calculations

Nitrogen exist as N₂ at room temperature, thus its molar mass is 2(14)= 28.

Let the rate and molar mass of unknown gas be Rate₂ and M₂ respectively.

Since N₂ effuses 1.7 times as fast as the unknown gas,

Rate₁= 1.7(Rate₂)

$\frac{Rate_1}{Rate_2} = 1.7$

$1. 7 = \sqrt{ \frac{M_2}{28} }$

Square both sides:

$2.89 = \frac{M_2}{28}$

Multiply both sides by 28:

2.89(28)= M₂

M₂= 80.92

Identity of gas

The molar mass of 80.92 lies between Bromine and Krypton. However since Bromine exist as Br₂, the value of it's molar mass would be 159.8 instead. Hence, Bromine is eliminated.

If the gas is a diatomic element, the atomic weight is 80.92 ÷2= 40.46. Thus, we are now considering if Argon could be its identity. However, Argon is a noble gas and will not exist as a diatomic element. Argon is therefore eliminated too.

Thus based on the above reasoning, its probable identity is Krypton.

7 0

2 years ago

The two boron atoms listed in the table are isotopes of the boron. The two carbon atoms and the two oxygen atoms are also called

Ivan

Answer:

A type of an atom which has a different number of neutrons but the same atomic number, therefore making it the same element. This atom would still have the same properties as well. (Ex: Vanadium-51 is an isotope of Vanadium that has 51 neutrons but still has 23 protons, as its atomic number is 23.)

3 0

2 years ago

1. What determines the reactivity of an atom?

Veronika [31]

The number of electrons in the outermost shell of an atom determines its reactivity.

5 0

3 years ago