How many moles of oxygen atoms are present in 5
moles of Mg3(PO4)2
All you have to do is to create
a ratio between the molecule and the oxygen atom.
5 moles of Mg3(PO4)2 (4x2 moles
O/1 mole Mg3(PO4)2) = 40 moles of oxygen
1 lb=453.592 grams
So he gained 453.592 pounds
Answer:
Gasoline combusting in an engine
Explanation:
When gasoline is ignited, carbon dioxide and water are produced.