The boiling point of water at 1 atm is 100 degrees celsius. However, when water is added with another substance the boiling point of it rises than when it is still a pure solvent. This called boiling point elevation, a colligative property. The equation for the boiling point elevation is expressed as the product of the ebullioscopic constant (0.52 degrees celsius / m) for water), the vant hoff factor and the concentration of solute (in terms of molality).
ΔT(CaCl2) = i x K x m = 3 x 0.52 x 0.25 = 0.39 °C
<span> ΔT(Sucrose) = 1 x 0.52 x 0.75 = 0.39 </span>°C<span>
</span><span> ΔT(Ethylene glycol) = 1 x 0.52 x 1 = 0.52 </span>°C<span>
</span><span> ΔT(CaCl2) = 3 x 0.52 x 0.50 = 0.78 </span>°C<span>
</span><span> ΔT(NaCl) = 2 x 0.52 x 0.25 = 0.26 </span>°C<span>
</span>
Thus, from the calculated values, we see that 0.75 mol sucrose dissolved on 1 kg water has the same boiling point with 0.25 mol CaCl2 dissolved in 1 kg water.
The lab coat is not thick enough to protect you from ionizing radiation.
<h3>What is radiation?</h3>
Radiation is a form of energy that we can not see with our optical eyes. We know that radiation could have a damaging effect on the body. The sort of radiation that could have a damaging effect on the body is what we call ionizing radiation.
We know that an ionizing radiation could only be stopped by a thick vest such as a lead coat. If you are wearing a lab coat, you are not safe because the lab cat is not thick enough to protect you from ionizing radiation.
Learn more about radiation:brainly.com/question/13934832
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I believe the answer is volatile!
True! all matter is made out of atoms & molecules
Answer:
PH scale is a universal indicator of strongness of base and acid
