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4 years ago

A 4.0 kg bucket of water is raised from a well

Physics

1 answer:

IrinaVladis [17]4 years ago

6 0

Explanation:

Draw a free body diagram of the bucket. There are two forces:

Tension force T pulling up.

Weight force mg pulling down.

Sum of forces in the y direction:

∑F = ma

T − mg = ma

T = mg + ma

T = m (g + a)

Given m = 4.0 kg, g = 9.81 m/s², and a = 2.8 m/s²:

T = (4.0 kg) (9.81 m/s² + 2.8 m/s²)

T = 50.44 N

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A piece of wood on top of an ocean wave stays in the same location, only moving up and down as the wave passes. It is energy tha

Ierofanga [76]

Answer:

Hey

Yes, this is true.

As some people have it wrong, waves in the water (ocean) are not waves of moving water, rather the wave is moving through the water. A wave is a disturbance of a medium not the meduim moving.

8 0

3 years ago

A boat race runs along a triangular course marked by buoys A, B, and C. The race starts with the boats headed west for 3700 mete

ale4655 [162]

Answer:

The last two bearings are

49.50° and 104.02°

Explanation:

Applying the Law of cosine (refer to the figure attached):

we have

x² = y² + z² - 2yz × cosX

here,

x, y and z represents the lengths of sides opposite to the angels X,Y and Z.

Thus we have,

$cos X=\frac{x^2-y^2-z^2}{-2yz}$

$cos X=\frac{y^2 + z^2-x^2}{2yz}$

substituting the values in the equation we get,

$cos X=\frac{2900^2 + 3700^2-1700^2}{2\times 2900\times 3700}$

$cos X=0.8951$

X = 26.47°

similarly,

$cos Y=\frac{1700^2 + 3700^2-2900^2}{2\times 1700\times 3700}$

$cos Y=0.649$

Y = 49.50°

Consequently, the angel Z = 180° - 49.50 - 26.47 = 104.02°

The bearing of 2 last legs of race are angels Y and Z.

7 0

3 years ago

Gold's natural state has a definite shape and a definite volume. What is gold's natural state(s)?

zysi [14]

solid

Explanation:

because it has a definite shape and volume

8 0

3 years ago

What is inertia? explain please!

MrRa [10]

Inertness, especially with regard to effort, motion, action, and the like; inactivity; sluggishness.

3 0

4 years ago

Read 2 more answers

6. A skier starts from rest at the top of a frictionless incline of height 20.0 m. At

n200080 [17]

Explanation:

a. KE at bottom = PE at top

½ mv² = mgh

v = √(2gh)

v = √(2 × 9.8 m/s² × 20.0 m)

v = 19.8 m/s

b. Work by friction = PE at top

mgμ d = mgh

d = h / μ

d = 20.0 m / 0.210

d = 95.2 m

6 0

3 years ago