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liraira [26]
2 years ago
8

3. The displacement of a particle is represented by s = at? + bts where t is time. Deduce the values of the constants a, and b.

Solution Hint: The summed quantities must all have the same dimension as s. Dimension of displacement s =. L ..., and t = ...I.......... .... ... = Equate dimension of s and at2 ; dim a= . ; dim b = ..... > Equate dimension of s and bt³​
Physics
1 answer:
barxatty [35]2 years ago
5 0

Explanation:

Correct option is

A

As LHS=RHS, formula is dimensionally correct.

Writing the dimensions of either side of the given equation.

LHS=8=displacement=[M

0

LT

0

]

RHS=ut=velocity×time=[M

0

LT

−1

][T]=[M

0

LT

0

]

and

2

1

at

2

=(acceleration)×(time)

2

=[M

0

LT

−2

][T]

2

=[M

0

LT

0

]

As LHS=RHS, formula is dimensionally correct.

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Given that a fluid at 260°F has a kinematic viscosity of 145 mm^2/s, determine its kinematic viscosity in SUS at 260°F.
Oduvanchick [21]

Answer:

kinematic viscosity in SUS is = 671.64 SUS

Explanation:

given data

kinetic viscosity = 145 mm^2/s

we know

1 mm = 0.1 cm

so kinetic viscosity in cm is \nu =145 (0.1)^{2} =1.45 cm^{2}/s

other unit of kinetic viscosity is centistokes

1 cm^{2}/s = 100 cst

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if the temperature is 260°f , then cst value should be multiplied by 4.632. therefore kinematic viscosity in SUS is = 4.362 *145 = 671.64 SUS

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3 years ago
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r-ruslan [8.4K]
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Licemer1 [7]

Answer:

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