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liraira [26]
3 years ago
8

3. The displacement of a particle is represented by s = at? + bts where t is time. Deduce the values of the constants a, and b.

Solution Hint: The summed quantities must all have the same dimension as s. Dimension of displacement s =. L ..., and t = ...I.......... .... ... = Equate dimension of s and at2 ; dim a= . ; dim b = ..... > Equate dimension of s and bt³​
Physics
1 answer:
barxatty [35]3 years ago
5 0

Explanation:

Correct option is

A

As LHS=RHS, formula is dimensionally correct.

Writing the dimensions of either side of the given equation.

LHS=8=displacement=[M

0

LT

0

]

RHS=ut=velocity×time=[M

0

LT

−1

][T]=[M

0

LT

0

]

and

2

1

at

2

=(acceleration)×(time)

2

=[M

0

LT

−2

][T]

2

=[M

0

LT

0

]

As LHS=RHS, formula is dimensionally correct.

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nataly862011 [7]

Answer: 45 joules of energy

Explanation:

6 0
3 years ago
The transfer of energy when particles of a fluid move from one place to another is called
siniylev [52]

Answer:

Answer below!!!!

Explanation:

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5 0
3 years ago
6.6 kg block initially at rest is pulled to theright along a horizontal, frictionless surfaceby a constant, horizontal force of
neonofarm [45]

Answer:

v = 3.04 m/s

Explanation:

given,

mass of the block, M = 6.6 Kg

horizontal force, F = 12.2 N

distance, L = 2.5 m

initial speed  = 0 m/s

speed of the block,v = ?

we now

Work done is equal to change in Kinetic energy.

Work done = Force x displacement

W = Δ K E

Δ K E = Force x displacement

\dfrac{1}{2}mv^2 - \dfrac{1}{2}mu^2= F .s

\dfrac{1}{2}\times 6.6 \times v^2 - 0= 12.2\times 2.5

 3.3 v² = 30.5

     v² = 9.242

      v = 3.04 m/s

speed of the block is equal to 3.04 m/s

4 0
3 years ago
A block on a horizontal frictionless plane is attached to a spring, as shown below. The block oscillates along the x-axis with s
AleksandrR [38]

The question is about unclear since no picture provided. But from the question, it could be guessed that the box is moving back and forth on the frictionless plane at the amplitude of A in simple harmonic motion.

Answer:

D. At x=0, it's acceleration is at a maximum

Explanation:

As the box move forward, it reaches point A and than move backward. Theoretically, the box will move backwards, through its origin, to point -A and then going forward.

Point A is the maximum displacement of the box in this case. At this point, the box instantaneously stop to go backward. Therefore the velocity at that moment is zero.

From point -A, the box travel forward and keep building up speed due to the release in potential energy of the spring. And at point x=0, the velocity become maximum. After point x=0, the velocity of the box slows down due to the conversion of kinetic energy to potential energy of the spring. And as it reaches point A, it reaches zero velocity.

The same can be said as the box travels backward from point A to -A

8 0
4 years ago
3) How far will 20 N of force stretch a spring with a spring constant of 140 N/m?
muminat

Answer:

7 meters, 2.8 meters

Explanation:

work done (nm) = force (n) * distance (m)

140= 20 * m

140/20 = m

m=7 meters

140= 50 * m

140/50 = m

m= 2.8 meters

4 0
2 years ago
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