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astra-53 [7]
3 years ago
8

Que factor produce los cambios en el movimiento de un cuerpo?

Physics
1 answer:
sergejj [24]3 years ago
5 0
D. Según la primer regla de Newton, la fuerza cambia el movimiento de un cuerpo.
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A bike first accelerates from 0.0m/s to 4.5m/s in 4.5 s, the continues at this constant speed for another 6.0 s. What is the tot
Alex_Xolod [135]

Answer:

37.125 m

Explanation:

Using the equation of motion

s=ut+0.5at^{2} where s is distance, u is initial velocity, t is time and a is acceleration

<u>Distance during acceleration</u>

Acceleration, a=\frac {V_{final}-V_{initial}}{t} where V_{final} is final velocity and V_{initial} is initial velocity.

Substituting 0.0 m/s for initial velocity and 4.5 m/s for final velocity, acceleration will be

a=\frac {4.5 m/s-0 m/s}{4.5 s}=1 m/s^{2}

Then substituting u for 0 m/s, t for 4.5 s and a for 1 m/s^{2} into the equation of motion

s=0*4.5+ 0.5*1*4.5^{2}=0+10.125 =10.125 m

<u>Distance at a constant speed</u>

At a constant speed, there's no acceleration and since speed=distance/time then distance is speed*time

Distance=4.5 m/s*6 s=27 m

<u>Total distance</u>

Total=27+10.125=37.125 m

3 0
3 years ago
What are moana's hobbies
crimeas [40]
The movie? Or the book
4 0
3 years ago
That 1.5 kg brick falls to the ground. What is the kinetic energy when the brick is moving at 26 m/s? Formula: Variables: Work w
Tresset [83]

Answer:

<h2>507 J</h2>

Explanation:

The kinetic energy of an object can be found by using the formula

k =  \frac{1}{2} m {v}^{2}  \\

m is the mass

v is the velocity

From the question we have

k =  \frac{1}{2}  \times 1.5 \times  {26}^{2}  \\  =  \frac{1}{2}  \times 1.5 \times 676 \\  = 1.5 \times 338  \\ = 507

We have the final answer as

<h3>507 J</h3>

Hope this helps you

5 0
3 years ago
A block of mass 12.2 kg is sliding at an initial velocity of 3.9 m/s in the positive x-direction. The surface has a coefficient
Studentka2010 [4]

Answer:

Explanation:

a) Force of friction = μ R where μ is coefficient of kinetic friction and R is reaction force

R = mg where m is mass of the block

Force of friction F = μ x mg

= .173 x 12.2 x 9.8

= 20.68 N

b ) Only force of friction is acting on the body so

deceleration = force / mass = 20.68 / 12.2 = 1.7 m /s²

acceleration = - 1.7 m /s²

c )

v² = u² - 2 a s

v = 0 , u = 3.9 m /s

a = 1.7 m /s

0 = 3.9² - 2 x 1.7 x s

s = 4.47  m

5 0
3 years ago
Hii please help i’ll give brainliest if you give a correct answer please please hurry it’s timed
Yanka [14]

Answer:

Sorry I'm wrong The person above is correct.

I tried.

4 0
3 years ago
Read 2 more answers
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