Answer:
Since incident wave and its reflected part in opposite phase superimpose on each other
So correct answer will be
Option B
Explanation:
Here we know that the wave reflection is done by rigid boundary
So when wave is reflected by the boundary then its phase is reversed by 180 degree
so the reflected wave is in reverse phase from the boundary
so we can superimpose the reflected part with incident wave to dine the resultant wave
So the phenomenon is given as follow
A) 2.64t
B) 2.64h
C) 2.64D
Explanation:
A)
The motion of the athlete is equivalent to the motion of a projectile, which consists of two independent motions:
- A uniform motion (constant velocity) along the horizontal direction
- A uniformly accelerated motion (constant acceleration) along the vertical direction
The time of flight of a projectile can be found from the equations of motion, and it is found to be
where
u is the initial speed
is the angle of projection
g is the acceleration due to gravity
In this problem, when the athlete is on the Earth, the time of flight is .
When she is on Mars, the acceleration due to gravity is:
where g is the acceleration due to gravity on Earth. Therefore, the time of flight on Mars will be:
B)
The maximum height reached by a projectile can be also found using the equations of motion, and it is given by
where
u is the initial speed
is the angle of projection
g is the acceleration due to gravity
In this problem, when the athlete is on the Earth, the maximum height is .
When she is on Mars, the acceleration due to gravity is:
where g is the acceleration due to gravity on Earth. So, the maximum height reached on Mars will be:
C)
The horizontal distance covered by a projectile is also found from the equations of motion, and it is given by
where:
u is the initial speed
is the angle of projection
g is the acceleration due to gravity
In this problem, when the athlete is on the Earth, the horizontal distance covered is D.
When she is on Mars, the acceleration due to gravity is:
where g is the acceleration due to gravity on Earth. Therefore, the horizontal distance reached on Mars will be:
