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Monica [59]
4 years ago
10

A body A of mass 1.5kg, travelling along the positive x-axis with speed 4.5m/s, collides with another body B of mass 3.2kg which

, initially, is at rest. As a result of the collision, A is deflected and moves with a speed 2.1m/s in a direction which is at angle 30° below the x-axis. B is set in motion at an angle θ above the x-axis. Calculate the velocity of B after the collision
Physics
1 answer:
Veronika [31]4 years ago
7 0
We consider the momentum in the x-direction and apply the principle of conservation of momentum to form the equation:
m(A)u(A) = m(A)v(A) + m(B)v(B), since u(B) = 0 as B is at rest

We calculate v(A) using:
Vx = Vcos∅
Vx = 2.1cos(30)
Vx = 1.82 m/s

1.5 x 4.5 = 1.5 x 1.82 + 3.2v(B)
v(B) = 1.26 m/s

The deflection angle of B will be 30° above the positive x-axis, so:
v(B) = Vcos∅
V = 1.26 / cos(30)
V = 1.45 m/s

The velocity of B is 1.45 m/s
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A spherical shell has an outside radius of 2.60 cm and an inside radius of a. The shell wall has uniform thickness and is made o
lbvjy [14]

Answer:

The answer is below

Explanation:

a) The volume of a sphere is:

Volume = (4/3)πr³; where r is the radius of the shell.

Given the outside radius of 2.60 cm and inner radius of a cm, the volume of the spherical shell is:

Volume of spherical shell = \frac{4}{3} \pi (2.6^3-a^3) cm³

But Density = mass / volume;   Mass = density * volume.

Therefore, mass of spherical shell = density * volume

mass of spherical shell = 4.70\ g/cm^3 * \frac{4}{3} \pi (2.6^3-a^3) cm³

Mass of liquid = volume of inner shell * density of liquid

Mass of liquid = \frac{4}{3} \pi a^3\ cm^3*1.23\ g/cm^3

Total mass of sphere including contents = mass of spherical shell + mass of liquid

Total mass of sphere including contents (M) = 4.70\ g/cm^3 * \frac{4}{3} \pi (2.6^3-a^3)\ cm^3  +  \frac{4}{3} \pi a^3\ cm^3*1.23\ g/cm^3 =

Total mass of sphere including contents (M) = (346 - 14.5a³) grams

b) The mass is maximum when the value of a = 0

M = 346 - 14.5a³

M' = 43.5a² = 0

43.5a² = 0

a = 0

4 0
3 years ago
All living organisms reproduce by a live functioning baby leaving the mother's body.​
algol13

Answer:

there is no question

Explanation:

4 0
3 years ago
. Orbit of a satellite It is advantageous to place communications satellites in a circular orbit so that their position is fixed
Alexxx [7]

Answer:

a) r = 4.22 10⁷ m, b)  v = 3.07 10³ m / s  and c)  a = 0.224 m / s²

Explanation:

a) For this exercise we will use Newton's second law where acceleration is centripetal and force is gravitational force

     F = m a

     a = v² / r

     F = G m M / r²

    G m M / r² = m v² / r

    G M / r = v²

The squared velocity is a scalar and this value is constant, so let's use the uniform motion relationships

     v = d / t

As the orbit is circular the distance is the length of the circle in 24 h time

     d = 2π r

     t = 24 h (3600 s / 1 h) = 86400 s

Let's replace

     G M / r = (2π r / t)²

     G M = 4 π² r³ / t²

     r = ∛(G M t² / (4π²)

     r = ∛( 6.67 10⁻¹¹ 5.98 10²⁴ 86400² / (4π²)) = ∛( 75.4 10²¹)

     r = 4.22 10⁷ m

b) the speed module is

    v = √G M / r

    v = √(6.67 10⁻¹¹ 5.98 10²⁴/ 4.22 10⁷

    v = 3.07 10³ m / s

c) the acceleration is

    a = G M / r²

    a = 6.67 10⁻¹¹ 5.98 10²⁴ / (4.22 10⁷)²

    a = 0.224 m / s²

5 0
3 years ago
Why is it that an object can accelerate while
posledela

For the same reason that you can skate around a curve at constant speed but not with constant velocity.

The DIRECTION you're going is part of your velocity, but it's not part of your speed.

If the DIRECTION changes, that's a change of velocity.

The object doesn't have to change speed to have a different velocity. A change of direction is enough to do it.

And any change of velocity is called acceleration.

3 0
3 years ago
Differentiate between:<br><br>a. Compression and Rarefaction<br>​
zlopas [31]

Answer:

Explanation:

Compression

The region in a medium where the distance between the vibrating molecules is minimum is compression.

This is the region with higher air pressure than the surrounding .

Rarefaction

The region in a medium where the distance between the vibrating molecules is maximum is rarefaction.

This is the region with relatively low air pressure.

hope it helps :)

7 0
3 years ago
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