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irakobra [83]
3 years ago
11

Consider the equation: 2 nan3 (s) 2 na (s) + 3 n2. what is the mass of nan3 needed to produce 17.2 l nitrogen at stp?

Chemistry
1 answer:
Lerok [7]3 years ago
3 0
The  mass  of NaN3  needed  to produce 17.2  L  nitrogen   at  STP is  calculated as  follows

find the  moles of N2   produced  at  STP
At  STP  1mole  of  gas =  22.4  L ,  what about  17.2 L  of  nitrogen

by cross  multiplication

= (1 mole x17.2  L)/ 22.4 L= 0.768  moles

2NaN3 =2Na  +3 N2
by   use of  mole ratio  between NaN3  to N2  (2:3) the  moles  of NaN3  =  0.768  x2/3 =  0.512  moles  of NaN3

mass of NaN3  is therefore =moles of NaN3  xmolar  mass of NaN3

=0.512moles  x 65 g/mol =33.28 grams  of NaN3



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3. A student carries out the clay-catalyzed dehydration of cyclohexanol starting with 10 moles of cyclohexanol and obtains 500 m
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Answer:

49.45~%

Explanation:

In this case, we have to start with the <u>chemical reaction</u>:

C_6H_1_2O~->~C_6H_1_0~+~H_2O

So, if we start with <u>10 mol of cyclohexanol</u> (C_6H_1_2O) we will obtain 10 mol of cyclohexanol (C_6H_1_0). So, we can calculate the grams of cyclohexanol if we<u> calculate the molar mass:</u>

(6*12)+(10*1)=82~g/mol

With this value we can calculate the grams:

10~mol~C_6H_1_0\frac{82~g~C_6H_1_0}{1~mol~C_6H_1_0}=820~g~C_6H_1_0

Now, we have as a product 500 mL of C_6H_1_0. If we use the <u>density value</u> (0.811 g/mL). We can calculate the grams of product:

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Finally, with these values we can calculate the <u>yield</u>:

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See figure 1

I hope it helps!

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