n oscillator is driven by a sinusoidal force. The frequency of the applied force A : must be less than the natural frequency of
1 answer:
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To solve this problem it is necessary to use the concepts related to the Hall Effect and Drift velocity, that is, at the speed that an electron reaches due to a magnetic field.
The drift velocity is given by the equation:
Where
I = current
n = Number of free electrons
A = Cross-Section Area
q = charge of proton
Our values are given by,
The hall voltage is given by
Where
B= Magnetic field
n = number of free electrons
d = distance
e = charge of electron
Then using the formula and replacing,
Answer:
48m
Explanation:
Given the following data;
Initial velocity = 0m/s
Final velocity = 6m/s
Time, t = 6 secs
Time, T2 = 5 secs
Mathematically, acceleration is given by the equation;
Substituting into the equation;
Acceleration, a = 1m/s²
<u>To find the distance covered in the first phase;</u>
<em>Solving for distance, we would use the second equation of motion;</em>
<em>Substituting the values into the equation;</em>
Distance, S1 = 18m
<u>For the second phase, time T2 = 5 secs;</u>
<em>Mathematically, speed is given by the equation;</em>
<em>Making distance the subject of formula, we have;</em>
<em>Substituting into the above equation;</em>
Distance, S2 = 30m
Total distance = S1 + S2 = 18m + 30m = 48m
Total distance = 48m
<em>Therefore, the total distance traveled by the biker is 48m.</em>
Answer:
When he weight of the car is 8.55 x N then power = 314.012 KW
When he weight of the car is 1.10 x N then power = 43.76 KW
Explanation:
Given that
Initial velocity = 0
Final velocity = 24.8
Time = 7.88 sec
We know that power required to accelerate the car is given by
P =
Change in kinetic energy Δ K.E =
Since Initial velocity = 0
⇒ Δ K.E =
⇒ Power P =
⇒ Power P = -------- (1)
(a). The weight of the car is 8.55 x N = 8550 N
Put all the values in above formula
So power P =
P = 314.012 KW
(b). The weight of the car is 1.10 x N = 11000 N
Put all the values in equation (1) we get
P =
P = 43.76 KW