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3 years ago

14

If jack was traveling north 120 miles and it took him 3 hours to get there. what is the velocity that jack was traveling? is thi

s a scalar or vector

1 answer:

Dimas [21]3 years ago

4 0

Answers:

40 mp/h; Vector

Reason:

120/3 is 40 miles per hour.

Velocity is a vector measurement.

^.^

- Amanda

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I am Lyosha [343]

The first one because the temperature of the water outside is higher than the one on the inside therefore the one on the inside is heating up

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3 years ago

An object in circular motion has velocity that is constantly changing. The direction of the acceleration is

sertanlavr [38]

An object in circular motion has velocity that is constantly changing.

The direction of the acceleration is from the object toward the center of the circular path the object is following.

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3 years ago

I throw a football in the x direction with a fore of 124N. The football is 4 kilograms. The football accelerated for 5 seconds.

castortr0y [4]

31 (unit)

acceleration formula

net force (124)

Acceleration = -------------

mass (4)

124÷4=31

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3 years ago

A magnetic field is uniform over a flat, horizontal circular region with a radius of 1.50 mm, and the field varies with time. In

Daniel [21]

Answer: $81.57\mu V$

Explanation:

Given

radius of circular region r=1.50 mm

$A=\pi r^2=7.069\times 10^{-6}\ m^2$

Magnetic Field $B=1.50\ T$

time t=130 ms

Flux is given by

$\phi =B\cdot A$

change in Flux $d\phi =(B_f-B_i)A$

Emf induced is $e=\frac{\mathrm{d} \phi}{\mathrm{d} t}$

$e=\frac{(1.5)\cdot 7.069\times 10^{-6}}{130\times 10^{-3}}$

$e=81.57 \mu V$

3 0

3 years ago

A 92kg astronaut and a 1200kg satellite are at rest relative to the space shuttle. The astronaut pushes on the satellite, giving

Harman [31]

Answer:

13.7m

Explanation:

Since there's no external force acting on the astronaut or the satellite, the momentum must be conserved before and after the push. Since both are at rest before, momentum is 0.

After the push

$m_av_a + m_sv_s = 0$

Where $m_a = 92kg$ is the mass of the astronaut, $m_s = 1200kg$ is the mass of the satellite, $v_s = 0.14 m/s$ is the speed of the satellite. We can calculate the speed $v_a$ of the astronaut:

$v_a = \frac{-m_sv_s}{m_a} = \frac{-1200*0.14}{92} = -1.83 m/s$

So the astronaut has a opposite direction with the satellite motion, which is further away from the shuttle. Since it takes 7.5 s for the astronaut to make contact with the shuttle, the distance would be

d = vt = 1.83 * 7.5 = 13.7 m

4 0

3 years ago