All categories

3 years ago

Whats a sound? i need help lol

Mathematics

2 answers:

Yanka [14]3 years ago

4 0

Answer:

In physics sound is a vibration that propagates as an acoustic wave so a transmission medium such as gas liquid or solid and human physiology and psychology sound is the reception In physics sound is a vibration that problem that propagates as an acoustic wave so a transmission medium such as gas liquid or solid and human physiology and psychology sound is the reception of waves of such waves and their In physics sound is a vibration that problem that propagates as an acoustic wave so a transmission medium such as gas liquid or solid and human physiology and psychology sound is the reception of waves of such waves and their perception by the brain sound ways between 20 Hz known as infrasound

ivann1987 [24]3 years ago

3 0

It’s the sensation produced by stimulation of the organs of hearing by vibrations transmitted through the air or other medium. ... the particular auditory effect produced by a given cause: the sound of music. any auditory effect; any audible vibrational disturbance: all kinds of sounds.

You might be interested in

Help i dunno the answer to it :

Novay_Z [31]

Answer:

5 miles per hour

Step-by-step explanation:

Let the speed of Kelly is $v_1$ miles per hour and speed of Raul is v₂ miles per hour.

Since, speed = $\frac{\text{Distance}}{\text{Time}}$

Kelly took 135 minutes to cover 90 miles from New York to Philadelphia.

∵ 1 minute = $\frac{1}{60}$ hours

∴ 135 minutes = $\frac{135}{60}$ = $\frac{9}{4}$ hours

v₁ = $\frac{90}{\frac{9}{4}}$

= $90\times \frac{4}{9}$

= 40 miles per hour

Raul took 153 minutes to cover the same distance as Kelly,

∵ 1 minute = $\frac{1}{60}$ hours

∴ 153 minutes = $\frac{153}{60}$ = $\frac{51}{20}$ hours

v₂ = $\frac{90}{\frac{51}{20}}$

$=90\times \frac{20}{51}$

= 35.29

≈ 35.3 miles per hours

v₁ - v₂ = 40 - 35.3

= 4.7

≈ 5.0 miles per hours

Therefore, Kelly is 5 miles per hours faster than Raul.

5 0

3 years ago

Read 2 more answers

HURRYYY i neeeeeddd helppppppppp look at the photo ^^^

Oliga [24]

Can you show a better photo some of the question is cut off

8 0

3 years ago

Read 2 more answers

The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e

irakobra [83]

Answer:

We need a sample size of at least 383.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

85% confidence level

So $\alpha = 0.15$ , z is the value of Z that has a pvalue of $1 - \frac{0.15}{2} = 0.925$ , so $Z = 1.44$ .

How large a sample would be required in order to estimate the fraction of tenth graders reading at or below the eighth grade level at the 85% confidence level with an error of at most 0.03

We need a sample size of at least n.

n is found with $M = 0.03, \pi = 0.21$