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3 years ago

Which sample of matter can be seperated into different substances by physical means

1 answer:

8 0

A mixture of matter. A mixture consists of two or more elements physically combined. Take salt water. It is a mixture. So just evaporate the salt water to dryness, it would be separated into salt and water. Hence, mixture can be separatedinto different substances by physical means. You can also use magnet.

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Which of the following statements correctly describes the relationship between volume and temperature( moles and pressure of gas

lorasvet [3.4K]

Answer:

pressure of gas are constant describe the relationship between moles and temprature

6 0

3 years ago

What statement correctly describes gravity

Gre4nikov [31]

Answer:

gravitation

Explanation:

5 0

3 years ago

Read 2 more answers

The second-order rate constants for the reaction of oxygen atoms witharomatic hydrocarbons have been measured (R. Atkinson and J

Pepsi [2]

Answer:

A = 1,13x10¹⁰

Ea = 16,7 kJ/mol

Explanation:

Using Arrhenius law:

ln k = -Ea/R × 1/T + ln(A)

You can graph ln rate constant in x vs 1/T in y to obtain slope: -Ea/R and intercept is ln(A).

Using the values you will obtain:

y = -2006,9 x +23,147

As R = 8,314472x10⁻³ kJ/molK:

-Ea/8,314472x10⁻³ kJ/molK = -2006,9 K⁻¹

Ea = 16,7 kJ/mol

Pre-exponential factor is:

ln A = 23,147

A = e^23,147

A = 1,13x10¹⁰

I hope it helps!

6 0

3 years ago

What volume would 3.00 moles of neon gas have at 295 K and 645 mmHg?

LUCKY_DIMON [66]

Answer:

V = 85.619 L

Explanation:

To solve, we can use the ideal gas law equation, PV = nRT.

P = pressure (645 mmHg)

V = volume (?)

n = amount of substance (3.00 mol)

R = ideal gas constant (62.4 L mmHg/mole K)

T = temperature (295K)

Now we would plug in the appropriate numbers into the equation using the information given and solve for V.

(645)(V) = (3.00)(62.4)(295)

(V) = (3.00)(62.4)(295)/645

V = 85.619 L

6 0

3 years ago

I NEED HELP PLEASE, THANKS! :)

krok68 [10]

Answer:

$\large \boxed{\text{2.20 g Pb}}$

Explanation:

They gave us the masses of two reactants and asked us to determine the mass of the product.

This looks like a limiting reactant problem.

1. Assemble the information

We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.

Mᵣ: 239.27 32.00 207.2

2PbS + 3O₂ ⟶ 2Pb + 2SO₃

m/g: 2.54 1.88

2. Calculate the moles of each reactant

$\text{Moles of PbS} = \text{2.54 g PbS } \times \dfrac{\text{1 mol PbS}}{\text{239.27 g PbS}} = \text{0.010 62 mol PbS}\\\\\text{Moles of O}_{2} = \text{1.88 g O}_{2} \times \dfrac{\text{1 mol O}_{2}}{\text{32.00 g O}_{2}} = \text{0.058 75 mol O}_{2}$

3. Calculate the moles of Pb from each reactant

$\textbf{From PbS:}\\\text{Moles of Pb} = \text{0.010 62 mol PbS} \times \dfrac{\text{2 mol Pb}}{\text{2 mol PbS}} = \text{0.010 62 mol Pb}\\\\\textbf{From O}_{2}:\\\text{Moles of Pb} =\text{0.058 75 mol O}_{2} \times \dfrac{\text{2 mol Pb}}{\text{3 mol O}_{2}}= \text{0.039 17 mol Pb}\\\\\text{PbS is the $\textbf{limiting reactant}$ because it gives fewer moles of Pb}$

4. Calculate the mass of Pb

$\text{ Mass of Pb} = \text{0.010 62 mol Pb} \times \dfrac{\text{207.2 g Pb}}{\text{1 mol Pb}} = \textbf{2.20 g Pb}\\\\\text{The reaction produces $\large \boxed{\textbf{2.20 g Pb}}$}$

5 0

3 years ago