This reduced fraction would be c. x+y/8.
You can apply the Difference of Two Squares Formula (x^2+y^2)=(x+y)(x-y). Then, you can factor out the common term 8 and cancel out the common factor x-y. Hope this helps! :)
Answer:
See the explanation below.
Step-by-step explanation:
Percentage of all the students landing point up 
Percentage of student ten landing point up 
Required Difference 

Step-by-step explanation:
2x - 3y - 2z = 4
[2] x + 3y + 2z = -7
[3] -4x - 4y - 2z = 10
Solve by Substitution :
// Solve equation [2] for the variable x
[2] x = -3y - 2z - 7
// Plug this in for variable x in equation [1]
[1] 2•(-3y-2z-7) - 3y - 2z = 4
[1] - 9y - 6z = 18
// Plug this in for variable x in equation [3]
[3] -4•(-3y-2z-7) - 4y - 2z = 10
[3] 8y + 6z = -18
// Solve equation [3] for the variable z
[3] 6z = -8y - 18
[3] z = -4y/3 - 3
// Plug this in for variable z in equation [1]
[1] - 9y - 6•(-4y/3-3) = 18
[1] - y = 0
// Solve equation [1] for the variable y
[1] y = 0
// By now we know this much :
x = -3y-2z-7
y = 0
z = -4y/3-3
// Use the y value to solve for z
z = -(4/3)(0)-3 = -3
// Use the y and z values to solve for x
x = -3(0)-2(-3)-7 = -1
Solution :
{x,y,z} = {-1,0,-3}
You can compare fractions by using the benchmark fraction of 1/2. To use this in order to make comparisons, you will need to look carefully at what the numerator and The denominators are in a fraction. If the top number, the numerator is less than half of the denominator, then the fraction would be less then the benchmark 1/2. If the numerator is more than half of the denominator then the fraction would be more than the benchmark 1/2. For example, 3/4 is more than 1/2 because the numerator of three is more than half of the denominator 4.
It will hit the ground after 3.499 seconds.
To solve this you first have to find the value of h(0) in this equation. That is the height from which it was dropped.
You can input any of the points into the equation and solve for the missing part. You will get 60 for the height.
The use the quadratic formula to see that it reaches the ground after 3.499 seconds.