The Thrust on the rocket is 1.434 MN.
To calculate the thrust of a rocket, we use the formula below
Thrust: This is the force that moves an aircraft through the air.
⇒Formula
- T = M'×v.................... Equation 1
⇒ Where:
- T = Thrust of the rocket
- M' = Fuel ejection rate
- v = gas exhaust velocity
From the question,
⇒ Given:
- M' = 239 kg/s
- v = 60 km/s = 6000 m/s
⇒ Substitute these values into equation 1
- T = 239(6000)
- T = 1434000 N
- T = 1.434 MN
Hence, the Thrust on the rocket is 1.434 MN.
Learn more about Thrust here: brainly.com/question/13501791
Answer:
6.93 volts
Explanation:
q = magnitude of charge on proton = 1.6 x 10⁻¹⁹ C
r = radius of the orbit = 2.08 x 10⁻¹⁰ m
V = Electric potential due to proton on electron
Electric potential due to proton on electron is given as
Inserting the values
V = 6.93 volts
Neptunes' average density is larger than that of Uranus. Hope this helps!
<h3>
Answer:</h3>
49500 kgm/s
<h3>
Explanation:</h3>
Data given;
- First car; Mass = 1100 kg
- Velocity = 30 m/s
- Second car; mass = 1100 kg
- Velocity = 15 m/s
We are required to calculate the total momentum of the system.
- We need to know that momentum is calculated by multiplying the velocity of a body by its mass.
- Therefore;
Momentum of the first car = 1100 kg × 30 m/s
= 33,000 kgm/s
Momentum of the second car = 1100 kg × 15 m/s
= 16,500 kgm/s
Therefore;
Total momentum = 33,000 kgm/s + 16,500 kgm/s
= 49500 kgm/s
Thus, the total momentum of the system is 49500 kgm/s
Answer:
Efficiency of the machine = 75%
Explanation:
Given:
Input work = 8,000 J
Output work = 6,000 J
Find:
Efficiency of the machine
Computation:
Efficiency of the machine = [Output work / Input work]100
Efficiency of the machine = [6,000 / 8,000]100
Efficiency of the machine = 75%
