<h2>When two object P and Q are supplied with the same quantity of heat, the temperature change in P is observed to be twice that of Q. The mass of P is half that of Q. The ratio of the specific heat capacity of P to Q</h2>
Explanation:
Specific heat capacity 
It is defined as amount of heat required to raise the temperature of a substance by one degree celsius .
It is given as :
Heat absorbed = mass of substance x specific heat capacity x rise in temperature 
or , 
Q= m x c x t 
In above question , it is given :
For Q 
mass of Q = m 
Temperature changed =T₂/2 
Heat supplied = x 
Q= mc t 
or 
X=m x C₁ X T₁ 
or, X =m x C₁ x T₂/2 
or, C₁=X x 2 /m x T₂                                 (equation 1 )
For another quantity : P 
mass of P =m/2 
Temperature= T₂ 
Heat supplied is same that is : X 
so, X= m/2 x C₂ x T₂                             
or, C₂=2X/m. T₂                                   (equation 2 )
Now taking ratio of C₂ to c₁, We have 
C₂/C₁= 2X /m.T₂  /2X  /m.T₂
so, C₂/C₁= 1/1 
so, the ratio is 1: 1