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VikaD [51]
3 years ago
11

A 1000 kg car’s velocity increases from 5 m/s to 10 m/s. What is the change to the car’s kinetic energy? Show your work.

Physics
1 answer:
katen-ka-za [31]3 years ago
3 0

Answer:

k. e. = 1/2 mv^2

1/2 * 1000 * (5)^2

1/2 * 1000 * 25

12500 joules

k. e. = 1/2 mv^2

1/2 * 1000 * (10)^2

1/2 * 1000 * 100

50000

change in k. e. = final - initial

50000 - 12500

= 37500 joules

hope it helps you

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A 1.50 kg rock is thrown up into the air from ground level, reaches a maximum height of 7.00 m, then returns to the ground. Calc
Minchanka [31]

Answer:

17.565 kgm/s

Explanation:

Momentum = mass × velocity

I = mv..................... Equation 1

But we can calculate the value of v  using the equation of motion under gravity.

v² =  u²+2gs............. Equation 2

Where u = initial velocity, s = maximum heigth, g = acceleration due to gravity.

Given: u = 0 m/s (at the maximum heigth), s = 7.0 m.

Constant: g = 9.8 m/s²

Substitute these values into equation 2

v² = 0²+ 2×7×9.8

v² = 137.2

v = √137.2

v = 11.71 m/s.

Also given: m = 1.50 kg

substitute these values into equation 1

Therefore,

I = 1.5×11.71

I = 17.565 kgm/s

3 0
2 years ago
A force of 30 N is exerted on an object on a frictionless surface for a distance of 6.0 meters. If the object has a mass of 10 k
tangare [24]

Answer:The velocity of the object will be 5\sqrt7m/s or 13.23m/s

Explanation:

force exerted by the object= 30N

distance displayed by the object by the action of force=6.0m

mass of object=10kg

velocity gained by the object=?

\frac{1}{2}mv^{2}= forcexdisplacement\\\frac{1}{2}10v^{2} = 30x6\\ 5v^{2}=180\\ v^{2}= 180-5\\ v^{2} =175\\v=\sqrt{175} \\v=5\sqrt{7} or 13.23

6 0
2 years ago
Do you think it is possible to determine an object is moving towards you, or moving away from you just by how it sounds? If
Nataly_w [17]

Answer:

I think so

Explanation:

When the object is moving towards you the sound gets louder but when it's moving away it sounds farther away.

6 0
3 years ago
a car takes off from rest and covers a distance of 80m on a straight road in 10s.calculate the magnitude of its acceleration
olasank [31]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

Here's the solution :

Let's find the final velocity :

  • \dfrac{displacement}{time}

  • \dfrac{80}{10}

  • 8 \:  \: ms {}^{ - 1}

Initial velocity (u) = 0 (cuz it started from rest)

Final velocity (v) = 8 m/s

Time taken (t) = 10 sec

now, we know that :

  • acceleration =  \dfrac{v - u}{t}

  • \dfrac{8 - 0}{10}

  • \dfrac{8}{10}

  • 0.8 \:  \: m {s}^{ - 2}

Acceleration = 0.8 m/s²

7 0
3 years ago
What happens to the light as it changes media from air to glass?
Dmitry [639]
Light is refracted when it crosses the interface from air into glass in which it moves more slowly. Since the light speed changes at the interface, the wavelength of the light must change, also. The wavelength decreases as the light enters the medium and the light wave changes direction.
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