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3 years ago

A 1000 kg car’s velocity increases from 5 m/s to 10 m/s. What is the change to the car’s kinetic energy? Show your work.

Physics

1 answer:

katen-ka-za [31]3 years ago

3 0

Answer:

k. e. = 1/2 mv^2

1/2 * 1000 * (5)^2

1/2 * 1000 * 25

12500 joules

k. e. = 1/2 mv^2

1/2 * 1000 * (10)^2

1/2 * 1000 * 100

50000

change in k. e. = final - initial

50000 - 12500

= 37500 joules

hope it helps you

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A 1.50 kg rock is thrown up into the air from ground level, reaches a maximum height of 7.00 m, then returns to the ground. Calc

Minchanka [31]

Answer:

17.565 kgm/s

Explanation:

Momentum = mass × velocity

I = mv..................... Equation 1

But we can calculate the value of v using the equation of motion under gravity.

v² = u²+2gs............. Equation 2

Where u = initial velocity, s = maximum heigth, g = acceleration due to gravity.

Given: u = 0 m/s (at the maximum heigth), s = 7.0 m.

Constant: g = 9.8 m/s²

Substitute these values into equation 2

v² = 0²+ 2×7×9.8

v² = 137.2

v = √137.2

v = 11.71 m/s.

Also given: m = 1.50 kg

substitute these values into equation 1

Therefore,

I = 1.5×11.71

I = 17.565 kgm/s

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2 years ago

A force of 30 N is exerted on an object on a frictionless surface for a distance of 6.0 meters. If the object has a mass of 10 k

tangare [24]

Answer:The velocity of the object will be 5 $\sqrt7$ m/s or 13.23m/s

Explanation:

force exerted by the object= 30N

distance displayed by the object by the action of force=6.0m

mass of object=10kg

velocity gained by the object=?

$\frac{1}{2}mv^{2}= forcexdisplacement\\\frac{1}{2}10v^{2} = 30x6\\ 5v^{2}=180\\ v^{2}= 180-5\\ v^{2} =175\\v=\sqrt{175} \\v=5\sqrt{7} or 13.23$

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2 years ago

Do you think it is possible to determine an object is moving towards you, or moving away from you just by how it sounds? If

Nataly_w [17]

Answer:

I think so

Explanation:

When the object is moving towards you the sound gets louder but when it's moving away it sounds farther away.

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3 years ago

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Here's the solution :

Let's find the final velocity :

$\dfrac{displacement}{time}$

$\dfrac{80}{10}$

$8 \: \: ms {}^{ - 1}$

Initial velocity (u) = 0 (cuz it started from rest)

Final velocity (v) = 8 m/s

Time taken (t) = 10 sec

now, we know that :

$acceleration = \dfrac{v - u}{t}$

$\dfrac{8 - 0}{10}$

$\dfrac{8}{10}$

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