Sorry don’t know hope you gave the answer to your questions
Answer:
a
Explanation:
a is he answers . mass and density
Explanation:
Use the height of the cliff to determine how long it took the car to land.
Take down to be positive. Given:
Δy = 7.93 m
v₀ = 0 m/s
a = 9.8 m/s²
Find: t
Δy = v₀ t + ½ at²
7.93 m = (0 m/s) t + ½ (9.8 m/s²) t²
t = 1.27 s
Use the time to calculate the horizontal velocity.
Given:
Δx = 26.7 m
a = 0 m/s²
Find: v₀
Δx = v₀ t + ½ at²
26.7 m = v₀ (1.27 s) + ½ (0 m/s²) (1.27 s)²
v₀ = 21.0 m/s
The driver was going 21.0 m/s, faster than the speed limit of 9.72 m/s.
Answer:
Explanation:
Initial velocity is 0. In the equation v = v0+at where v0 is the initial velocity of 0, we only have to fill in -9.8 for a and 2 for t to get the velocity after 2 seconds -19.6 m/s; after 5 seconds, when it hits the ground, a = -9.8 and t = 5 to give a velocity of -49 m/s. Gravity pulls down everything at the same rate, it doesn't matter whether we drop a feather or an elephant from the window!
Answer:
Time period of the osculation will be 0.0671 sec
Explanation:
It is given a vertical spring is stretched by 4 cm
So change in length of the spring x = 4 cm = 0.04 m
Mass which is hung from it m = 12 gram = 0.012 kg
Sprig force will be equal to weight of the mass
So 
k = 244.7 N/m
Now new mass is m = 28 gram = 0.028 kg
So time period with new mass will be
