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3 years ago

Is distance traveled by a moving train qualitative discrete continuous or na?

1 answer:

8 0

Continuous. Discrete values are values like 1, 2, 3, 4, etc. - they're values that are distinct, and typically there's some idea of a next and a previous value. When we're counting whole numbers, there's a definitive answer to which number comes after, and which number comes before. With continuous values, there's no real "next" or "last" value.

Motion is measured with continuous values; a train might move 300 yards in 1 minute, but we can look at smaller and smaller chunks of time to keep getting shorter and shorter distances. There is no "next" distance the train moves after those 300 yards - it just doesn't make sense for there to be.

It's also measured quantitatively, not qualitatively. This just means that we can use numerical values to measure it, rather than other descriptors like color, smell, or taste.

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If the amplitude of a sound wave is tripled, by what factor will the intensity increase?

Shtirlitz [24]

Answer:

By a factor 9

Explanation:

The intensity of a sound wave is proportional to the square of the amplitude of the wave:

$I \propto A^2$

where

I is the intensity

A is the amplitude of the wave

In this problem, the amplitude of the sound wave is increased by a factor 3:

A' = 3A

So the intensity would change by

$I' \propto A'^2 = (3A)^2 = 9 A^2 = 9I$

So, the intensity would increase by a factor 9.

5 0

3 years ago

A baseball player hits a homerun, and the ball lands in the left field seats, which is 103m away from the point at which the bal

Sati [7]

(a) The ball has a final velocity vector

$\mathbf v_f=v_{x,f}\,\mathbf i+v_{y,f}\,\mathbf j$

with horizontal and vertical components, respectively,

$v_{x,f}=\left(20.5\dfrac{\rm m}{\rm s}\right)\cos(-38^\circ)\approx16.2\dfrac{\rm m}{\rm s}$

$v_{y,f}=\left(20.5\dfrac{\rm m}{\rm s}\right)\sin(-38^\circ)\approx-12.6\dfrac{\rm m}{\rm s}$

The horizontal component of the ball's velocity is constant throughout its trajectory, so $v_{x,i}=v_{x,f}$ , and the horizontal distance x that it covers after time t is

$x=v_{x,i}t=v_{x,f}t$

It lands 103 m away from where it's hit, so we can determine the time it it spends in the air:

$103\,\mathrm m=\left(16.2\dfrac{\rm m}{\rm s}\right)t\implies t\approx6.38\,\mathrm s$

The vertical component of the ball's velocity at time t is

$v_{y,f}=v_{y,i}-gt$

where g = 9.80 m/s² is the magnitude of the acceleration due to gravity. Solve for the vertical component of the initial velocity:

$-12.6\dfrac{\rm m}{\rm s}=v_{y,i}-\left(9.80\dfrac{\rm m}{\mathrm s^2}\right)(6.38\,\mathrm s)\implies v_{y,i}\approx49.9\dfrac{\rm m}{\rm s}$

So, the initial velocity vector is

$\mathbf v_i=v_{x,i}\,\mathbf i+v_{y,i}\,\mathbf j=\left(16.2\dfrac{\rm m}{\rm s}\right)\,\mathbf i+\left(49.9\dfrac{\rm m}{\rm s}\right)\,\mathbf j$

which carries an initial speed of

$\|\mathbf v_i\|=\sqrt{{v_{x,i}}^2+{v_{y,i}}^2}\approx\boxed{52.4\dfrac{\rm m}{\rm s}}$

and direction θ such that

$\tan\theta=\dfrac{v_{y,i}}{v_{x,i}}\implies\theta\approx\boxed{72.0^\circ}$

(b) I assume you're supposed to find the height of the ball when it lands in the seats. The ball's height y at time t is

$y=v_{y,i}t-\dfrac12gt^2$

so that when it lands in the seats at t ≈ 6.38 s, it has a height of

$y=\left(49.9\dfrac{\rm m}{\rm s}\right)(6.38\,\mathrm s)-\dfrac12\left(9.80\dfrac{\rm m}{\mathrm s^2}\right)(6.38\,\mathrm s)^2\approx\boxed{119\,\mathrm m}$

6 0

3 years ago

Explain how temperature changes affect the ice on a lake ?

KengaRu [80]

Well if it gets warmer the ice will weaken and if it gets hot enough will melt. Of course if the weather gets colder the ice will thicken.

7 0

3 years ago

Aray diagram is shown. Medium 2 Medium 1 Which statement best describes the diagram?

Lady bird [3.3K]

if we can't see air do fish see water ?

6 0

4 years ago

If you graph the average velocity (y-axis) vs. the elapsed time (x-axis), what

Aleks [24]

Answer:

a diagonal line on the graph

Explanation:

the slope would be constant at an increasing rate

y=x

uniform= increasing at a constant rate

4 0

4 years ago