Answer:
The change in entropy ΔS = 0.0011 kJ/(kg·K)
Explanation:
The given information are;
The mass of water at 20.0°C = 1.0 kg
The mass of water at 80.0°C = 2.0 kg
The heat content per kg of each of the mass of water is given as follows;
The heat content of the mass of water at 20.0°C = h₁ = 83.92 KJ/kg
The heat content of the mass of water at 80.0°C = h₂ = 334.949 KJ/kg
Therefore, the total heat of the the two bodies = 83.92 + 2*334.949 = 753.818 kJ/kg
The heat energy of the mixture =
1 × 4200 × (T - 20) = 2 × 4200 × (80 - T)
∴ T = 60°C
The heat content, of the water at 60° = 251.154 kJ/kg
Therefore, the heat content of water in the 3 kg of the mixture = 3 × 251.154 = 753.462
The change in entropy ΔS = ΔH/T = (753.818 - 753.462)/(60 + 273.15) = 0.0011 kJ/(kg·K).
Knowing that the greatest horizontal pressure is the pressure made by the material on the wall -considering for that the total height of the wall-, then P = 4.375 t/m
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<u>Available data</u>:
- The wall is 5m long into the plane ⇒ H
- The soil density is 1.4 metric tonnes per cubic metre ⇒ γ
- K = 0.25 ⇒ Coefficient of earth pressure. Depends on the angle.
From this information, we need to calculate the greatest horizontal pressure.
Horizontal pressure refers to the force made by the supported soil on the retaining wall that tends to deflect the wall outward.
We can calculate horizontal pressure at different heights from the top. And since we need to calculate the greatest horizontal pressure, we need to consider the total height that equals the wall height, H.
To do it, we will use the following formula, and replace the terms.
P = [ k
γ H² ] / 2
P = [ 0.25 x 1.4 t/m³ x 5m² ] / 2
P = 8.75/2
P = 4.375 t/m
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