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myrzilka [38]
3 years ago
12

In a metallic bond, electrons

Chemistry
1 answer:
kobusy [5.1K]3 years ago
8 0
The answer would be c
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Anyone can help me please
Vlad1618 [11]

x=3

Use the pythagorean theorem:

a^2 + b^2 = c^2

4^2 + x^2 = 5^2

16 + x^2 = 25

x^2 = 25-16

x^2 = 9

√x^2 = √9

x = 3

5 0
3 years ago
In addition to content, elements also support _______ that specify the use, the behavior, and in some cases the appearance of an
a_sh-v [17]
In addition to content, elements also support attributes <span>that specify the use, the behavior, and in some cases the appearance of an element.
The other options just do not fit the blank in this question, which is why the word <em>attributes </em>is the correct one to choose here.</span>
3 0
3 years ago
If a large marshmallow has a volume of 2.00 in3 and density of 0.242 g/cm3, how much would it weigh in grams? 1 in3=16.39 cm3.
siniylev [52]

First convert the inches cubed to centimeters cubed. Looking at the rate, we can write 2 inches cubed = 2 * 16.39 cm cubed = 32.78 cm cubed.

The equation for density is D = M/V, where D is the density, M is the mass, and V is the volume. Substitute the values into the equation:

0.242 = M/32.78

Multiply by 32.78 on both sides.

The mass is about 7.93 grams.

3 0
3 years ago
Read 2 more answers
Calculate the empirical formula of a compound that is 42.9% Carbon and 57.1% Oxygen.
Marrrta [24]

Answer:

CO.

Explanation:

Assuming the given percentages are by mass, we can solve this problem via imagining we have <em>100 g of the compound</em>, if that were the case we would have:

  • 42.9 g of C
  • 57.1 g of O

Now we <u>convert those masses into moles</u>, using the<em> elements' respective molar masses</em>:

  • 42.9 g of C ÷ 12 g/mol =  3.57 mol C
  • 57.1 g of O ÷ 16 g/mol =  3.58 mol O

As the number of C moles and O moles is roughly the same, the empirical formula for the compound is <em>CO</em>.

4 0
3 years ago
What is the meaning of acid?​
weqwewe [10]

Answer:

a substance which when dissolved with water makes H+ ions

7 0
3 years ago
Read 2 more answers
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