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krek1111 [17]
3 years ago
13

Technician A says that for best results, loosen the fastener immediately after spraying it with penetrating oil. Technician B sa

ys that rusted fasteners may be loosened by tapping with a hammer. Which technician is correct?
a. technician A only
b. technician B only
c. both technicians A and B
d. neither technician A nor B
Physics
1 answer:
yarga [219]3 years ago
3 0

Answer:

C. Both Technicians A and B

Explanation:

To loosen a fastener immediately especially if it is a rusted one we can follow these steps.

1. Tap the sides of the fastener so that the rust particle fall off.

2. These rust particles can be brushed off.

3. Spray the fastener with the penetrating oil.

4. Again tap the sides with a hammer to let the oil penetrate the inter-locked parts (threads in case of a nut and bolt).

5. Loosen the fastener after oil has penetrated.

Note: It should be kept in consideration that spraying alone won't do the job, tapping is essential to let the oil penetrate deep in to free the rusted parts.

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The human eye can readily detect wavelengths from about 400 nm to 700 nm. If white light illuminates a diffraction grating havin
nadya68 [22]

Answer:

The range of angles is from 17.50° to 31.76°

Explanation:

The diffraction grid equation is as follows:

dsen\theta=m\lambda

Clearing for \theta

sen\theta=\frac{m\lambda}{d}

\theta=sen^{-1}(\frac{m\lambda}{d})

where \theta is the angle, m is the order, in this case m=1, \lambda is the wavelength, and d is defined as follows:

d=\frac{1}{resolution}

and since the resolution is 750 lines/mm wich is the same as 750lines/1x10^{-3}m

d will be:

d=\frac{1}{750lines/1x10^{-3}m}=\frac{1x10^{-3}m}{750lines}=1.33x10^{-6}m

wich is the distance between each line of the diffraction grating.

substituting the values for m and d:

\theta=sen^{-1}(\frac{(1)\lambda}{(1.33x10^{-6}m)})

And we need to find two angle values: one for when the wavelength is 400nm and one for when it is 700 nm. So we will get the angle range

\theta=sen^{-1}(\frac{(400x10^{-9})}{(1.33x10^{-6}m)})=17.50

and

\theta=sen^{-1}(\frac{(700x10^{-9})}{(1.33x10^{-6}m)})=31.76

The range of angles is from 17.50° to 31.76°

3 0
3 years ago
Which of the following is a common human relations mistake?
lys-0071 [83]
The correct answer should be A. Misjudging others' abilities

Taking responsibility when you make a mistake and listening to your supervisor are a must in the adult world while saying thank you is not a mistake but rather a trait. Misjudging others' abilities can sometimes even be offensive and is common as a mistake.
8 0
3 years ago
Read 2 more answers
Momentum of 0.5 kg moving ball with the velocity of 5 m / s ​
ankoles [38]

Answer:

2.5

Explanation:

Momentum = Mass × Velocity

3 0
2 years ago
Read 2 more answers
On the 1-to-10-billion scale, about how far is it to the nearest stars besides the sun? on the 1-to-10-billion scale, about how
aliina [53]
Not sure what your question means but the nearest star is Alpha Centauri which is about 4.2 light years (ly) away.  This is roughly 4x10¹³ km away.  A billion is 10⁹ so this is 4x10⁴ larger than a billion.  I'd say the last one then...
8 0
3 years ago
The product of voltage times amperage is known as what?
Usimov [2.4K]

Answer:

Power=V*I which corresponds to the second option shown: "voltage times amperage"

Explanation:

The electric power is the work done to move a charge Q across a given difference of potential V per unit of time.

Since such electrical work is the product of the potential difference V times the charge that moves through that potential, and this work is to be calculated by the unit of time, we need to divide the product by time (t) which leads to the following final simple equation

Power=\frac{V\,Q}{t} =V\,\frac{Q}{t} = V\, I

5 0
3 years ago
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