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tensa zangetsu [6.8K]
2 years ago
14

A car takes off from a stop sign and is going 267 m/s after 4.5 seconds. a) Determine the acceleration of the car. Show your wor

k and include units
Physics
1 answer:
gizmo_the_mogwai [7]2 years ago
3 0

Answer:

49.33333m/s²

Explanation:

The formula for acceleration is <em>acceleration=change in velocity/change in time</em>

<em>So: </em>

<em>Iv= 0m/s</em>

<em>Fv= 267m/s</em>

<em>a=267m/s divided by 4.5s</em>

<em>a=49.3333m/s²</em>

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3 years ago
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Answer:

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Explanation:

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Acceleration

a=-\frac{f}{m}\\\Rightarrow a=-\frac{\mu mg}{m}\\\Rightarrow a=-\mu g

a=--9.81\times 0.48=4.7088\ m/s^2

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v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 4.7088\times 0.935+0^2}\\\Rightarrow v=2.96739\ m/s

In this system the momentum is conserved

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The speed of the bean bag is 31.42383 m/s

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Answer:

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