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tensa zangetsu [6.8K]

3 years ago

14

A car takes off from a stop sign and is going 267 m/s after 4.5 seconds. a) Determine the acceleration of the car. Show your wor

k and include units

1 answer:

gizmo_the_mogwai [7]3 years ago

3 0

Answer:

49.33333m/s²

Explanation:

The formula for acceleration is <em>acceleration=change in velocity/change in time</em>

<em>So: </em>

<em>Iv= 0m/s</em>

<em>Fv= 267m/s</em>

<em>a=267m/s divided by 4.5s</em>

<em>a=49.3333m/s²</em>

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The edge of a flying disc with a radius of 0.13 m spins with a tangential speed of 3.3 m/s. The centripetal acceleration of the

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Answer:

Centripetal acceleration = 83.77m/s²

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<u>Given the following data;</u>

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Object A has a mass m and a speed v, object B has a mass m/2 and a speed 4v, and object C has a mass 3m and a speed v/3. Rank th

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<h2>The rank is : $P_B>P_A=P_C$ .</h2>

We need to rank the objects according to the magnitude of their momentum.

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Momentum of object A , $P_A = m v.$

Momentum of object B , $P_B= \dfrac{m}{2}\times4v=2\ mv.$

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Now, we can rank them in order of their magnitude of momentum .

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